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Yakvenalex [24]
2 years ago
6

A box of nine iPhone 5C cellphones (the iPhone “for the colorful”) contains two yellow cellphones and seven green cellphones. (a

) If two cellphones are randomly selected from the box, without replacement (the first cellphone is not returned to the box after it is selected), what is the probability that both cellphones selected will be green? (b) If two cellphones are randomly selected from the box, without replacement (the first cellphone is not returned to the box after it is selected), what is the probability that there will be one yellow cellphone and one green cellphone selected? (c) If three cellphones are selected, with replacement (the first cellphones are returned to the box after it is selected), what is the probability that all three will be yellow? (d) If you were sampling with replacement (the first cellphone is returned to the box after it is selected), what would be the answers to (a) and (b)? 3
SAT
1 answer:
fenix001 [56]2 years ago
8 0
On it uioooopliuiioiuyyukkppoloowp we o ok G G ooui a no saS as as sAqqa awe we e it
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Answer:

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Explanation:

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3 years ago
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the following data give the hours spent studying per week by nine students. 12, 16, 7, 22, 11, 18, 7, 25, 16. (a) find the mean,
Anton [14]

Answer:

Mean: 14.8888888889

Median: 16

Mode: 7,16

Range: 18

Explanation:

7,7,11,12,16,16,18,22,25

Mean: (7+7+11+12+16+16+18+22+25)/9

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nika2105 [10]

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What maximum amount of ammonia in kilograms can be synthesized from 5.22 kg of h2 and 31.5 kg of n2?
Fiesta28 [93]

Consider the unbalanced reaction,

H₂ + N₂   ===>   NH₃

Balance it to get

3 H₂ + N₂   ===>   2 NH₃

This tells you that for every 3 moles of H₂ and 1 mole of N₂ among the reactants, 2 moles of NH₃ are produced.

Look up the molar masses of each component element:

• H : 1.008 g/mol     ===>   H₂ : 2.016 g/mol

• N : 14.007 g/mol     ===>   N₂ : 28.014 g/mol

• NH₃ : 17.031 g/mol

Convert the given mass to moles for each reactant:

• H₂ :

(5.22 kg) × (1000 g/kg) × (1/2.016 mol/g) ≈ 2589.29 mol

• N₂ :

(31.5 kg) × (1000 g/kg) × (1/28.014 mol/g) ≈ 1124.44 mol

Now,

(2589.29 mol H₂) : (1124.44 mol N₂) ≈ (2.30 mol H₂) : (1 mol N₂)

so that the amount of N₂ consumed is

(2589.29 mol H₂) × (1 mol N₂) / (3 mol H₂) ≈ 863.095 mol N₂

leaving an excess of about 261.343 mol N₂, and producing

(2589.29 mol H₂) × (2 mol NH₃) / (3 mol H₂) ≈ 1726.19 mol NH₃

Convert this to a mass :

(1726.19 mol) × (17.031 g/mol) × (1/1000 kg/g) ≈ 29.3987 kg

So, up to 29.4 kg of NH₃ can be synthesized.

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when researching a career goal it it probably most important to ask what you will need for this career
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