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tresset_1 [31]
2 years ago
11

18. MP Reason Inductively The product of

Mathematics
1 answer:
timama [110]2 years ago
6 0

Answer:

- 2 and 12

Step-by-step explanation:

let the 2 integers be x and y , x > y , then

x - y = 14 → (1)

x + y = 10 → (2)

add the 2 equations term by term to eliminate y

2x = 24 ( divide both sides by 2 )

x = 12

Substitute x = 12 into (2)

12 + y = 10 ( subtract 12 from both sides )

y = - 2

As a check

x + y = 12 + (- 2) = 12 - 2 = 10

x - y = 12 - (- 2) = 12 + 2 = 14

xy = 12 × - 2 = - 24

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According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 15x11 – 6x8 + x3 – 4x + 3?
scoundrel [369]

we have

f(x) = 15x^{11} -6x^{8} + x^{3} - 4x + 3

we know that

<u>The Rational Root Theorem</u> states that when a root 'x' is written as a fraction in lowest terms

x=\frac{p}{q}

p is an integer factor of the constant term, and q is an integer factor of the coefficient of the first monomial.

So

in this problem

the constant term is equal to 3

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So

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therefore

<u>the answer is</u>

The all potential rational roots of f(x) are

(+/-)\frac{1}{15},(+/-)\frac{1}{5},(+/-)\frac{1}{3},(+/-)\frac{3}{5},(+/-)1,(+/-)3


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