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Fofino [41]
3 years ago
14

CAN SOMEONE HELP ME PLEASE ASAP!?

Mathematics
1 answer:
VikaD [51]3 years ago
8 0

Answer:

40°

Step-by-step explanation:

∠AOE and ∠COD are vertical angles meaning they have the same value.

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Samantha’s college runs on a trimester schedule so she receives a bill 3 times a year for tuition. Each trimester costs $1,450,
matrenka [14]

3 times a year for 2 years is equal to 3 x 2, or 6. So we know that she will have to pay her bill 6 times.

The cost for each trimester is $1450, but we still have to add the book costs ($350). So, 1450 + 350 = 1800.

Now we know that she has to pay $1800 six times. So the equation will be:

1800 x 6 = 10800.

It will cost Samantha $10,800 to get her degree.

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1 6 36 216 what come next
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The answer will be 346
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6051 m is equal to how many km?
Luba_88 [7]
6,051m = 6,000m + 51m

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Write an expression using all six trigonometric functions such that the value of the expression is 3.
iren2701 [21]
The trig functions that you need to deal with are
Sine
Cosine
Tangent
Cotangent
Cosecant
Secant

You need to write a single expression using all six trig functions such that the value of the expression equals 3.

To make this as simple as possible, the first thing I would do is look up the values of these functions and identify which ones are equal to either 1/2 or 1.0 or 2.0

sin(30º) = 1/2
sin(90º) = 1
cos(0º) = 1
cos(60º) = 1/2
tan(45º) = 1
csc(30º) = 2
csc(90º) = 1
sec(0º) = 1
sec(60º) = 2
cot(45º) = 1

If we only had to use three trig functions (sin, cos, tan), one possibility is
tan(45º) + cos(0º)/sin(30º) = 1 + 1/(1/2) = 1 + 2 = 3
noticed how I chose one each of the required functions and the operations so that the result = 3.

Now it is up to you to figure out how to combine all six trig functions so that they equal zero. There are many possibilities for you to choose from..
6 0
3 years ago
12. A carpenter made two tables. The first table is 4 feet
Arte-miy333 [17]

Answer:

a. True

b. True

c. False

d. False

Step-by-step explanation:

<u>First Table</u>

Length=10 feet, Width=4 feet

Area =10 X 4=40 Square Feet

<u>Second Table</u>

The second table is half as long  as the first table.

Length =0.5 X 10 =5 feet

Area=5 X Width= 5w

The area of the second table is one  fourth the area of the first table.

Area of Second Table =\frac{1}{4} X Area of first table

5w=\frac{1}{4} X 40

5w=10

Width of the Second table, w=2 feet

The following are true.

(a)The width of the second  table is 2 feet.

(b) The area of the second  table is 10 square feet.

6 0
3 years ago
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