24. Yes, they are congruent by the AAS postulate/statement
26. 3/4.5 = 5.2/a -> m-e thm. -> mult. POC -> a = 7.8 in.
30. pythagorean thm. -> 2² + b² = 2.5² -> b = 1.5 m
32. a) v = 1/3πr²h -> v = 1/3*3.14*4.5²*6 (6 is found w/ pythagorean thm.) -> v ≈ 127.2 cm³
b) yes, 130 cm³ > 127.2 cm³
33. a) 4.5/r = 2/7 -> 4.5/2 = r/7 -> 15.75 ≈ 15.8 in.
b) due to the cones being similar in shape, all one-dimensional measurements will be the same, thus, it is 2:7.
Answer:
<u>42.25π m²</u>
Step-by-step explanation:
Let's solve!
⇒ Take the radius of the lawn to be 'r'
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Then, area of the path equals :
⇒ Area of (lawn + path) - Area of lawn
⇒ π (r + 2)² - πr² = 30π
⇒ πr² - πr² + 4πr + 4π = 30π
⇒ 4πr = 26π
⇒ r = 6.5 m
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Area of the lawn :
⇒ Area = πr²
⇒ Area = π × (6.5)²
⇒ Area = <u>42.25π m²</u>
Answer:
It would take 5.5 months for the two cable companies to cost the same.
Step-by-step explanation:
50x + 100 = 60x + 45
-45 -45
50x + 55 = 60x
-50x -50x
55 = 10x
/10 /10
x = 5.5
Answer:
B
Step-by-step explanation:
y= -24/x²+8
y-<em>i</em><em>n</em><em>t</em><em> </em><em>(</em><em> </em><em>0</em><em>,</em><em>-</em><em>3</em>