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Ket [755]
2 years ago
12

Algebra: Explain in words how to write an equation that is part one: parallel and then also part two: perpendicular to the equat

ion y=2/3x-4 passing through the point (-2,-5). Write the answer in standard form.
Mathematics
1 answer:
sweet-ann [11.9K]2 years ago
8 0
A line that is parallel has the same slop where a line that is perpendicular has a slop that is negative and reciprocal.

so for the parallel one you don't need to worry about the slop because it will be 2/3x. But yous the point slope equation form

y-y1=m(x-x1)

y+5=2/3(x+2)

y+5=2/3x+ 4/3

y=2/3x-11/3

-2/3x+y=-11/3

multiple by -1 so A inst negative

2/3-y=11/3

For a line that is perpendicular you just need to flip the original 2/3x slope and make it negative.

y+5=-3/2(x+2)

y+5=-3/2x-3

y=-3/2x-8

3/2x+y=-8
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ANSWER

y \leqslant   - 2x - 2

EXPLANATION

The boundary line passes through (-2,2) and (0,-2).

The slope of this line is

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The slope-intercept form of this line is given by;

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Since the lower half-plane is shaded the required inequality is

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Step-by-step explanation:

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Will mark brainliest and 15 points
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Step-by-step explanation:

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