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3 years ago

Where is the point (0, -5) located on the coordinate plane?

Mathematics

1 answer:

Anna007 [38]3 years ago

3 0

On the y-axis.

Hope this helps!!

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Equivalent expression for 5a+30

ryzh [129]

Answer:

5a +30

take 5 common

5( a+6)

4 0

3 years ago

Tim is designing a logo. The logo is a polygon. Whose shape is a square attached to an equilateral triangle. The square and the

Sauron [17]

Given:
2 shapes : square and equilateral triangle
side length = 2 cm
height of equilateral triangle = 1.7 cm

Equilateral triangle means that all sides are of equal measurement.

Area of a Square = a² ⇒ (2cm)² = 4cm²
Area of an equilateral triangle = √3/4 * a²
Area of an equilateral triangle = √3/4 * (2cm)² = 0.43 * 4cm² = 1.72 cm²

Area of the logo = 4 cm² + 1.72 cm² = 5.72 cm²

4 0

3 years ago

A triangle has a base of 5 centimeters and a height of 8 centimeters.

Aleks04 [339]

Answer:

C. 20 cm^2 is the area. Hope this helped you.

6 0

3 years ago

Read 2 more answers

Who knows how to do this ughhh I need help!

suter [353]

Answer:

$\large\boxed{\sqrt{56x^{17}}=2x^8\sqrt{14x}}$

Step-by-step explanation:

$Domain:\ x\geq0\\\\\sqrt{56x^{17}}=\sqrt{4\cdot14\cdot x^{16+1}}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{4\cdot14\cdot x^{16}\cdot x^1}\\\\\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt4\cdot\sqrt{14}\cdot\sqrt{x^{16}}\cdot\sqrt{x}=2\cdot\sqrt{14}\cdot\sqrt{x^{8\cdot2}}\cdot\sqrt{x}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=2\cdot\sqrt{14}\cdot\sqrt{(x^8)^2}\cdot\sqrt{x}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=2\cdot\sqrt{14}\cdot x^8\cdot\sqrt{x}=2x^8\sqrt{14x}$

8 0

3 years ago

Verify that [tan(theta) + cot(theta)]^2 = sec^2(theta) + csc^2(theta)

Wittaler [7]

(tanθ + cotθ)² = sec²θ + csc²θ

Expand left side: tan²θ + 2tanθcotθ + cot²θ

Evaluate middle term: 2tanθcotθ = $2*\frac{sin\theta}{cos\theta}*\frac{cos\theta}{sin\theta}$ = 2

⇒ tan²θ + 2+ cot²θ

= tan²θ + 1 + 1 + cot²θ

Apply trig identity: tan²θ + 1 = sec²θ

⇒ sec²θ + 1 + cot²θ

Apply trig identity: 1 + cot²θ = csc²θ

⇒ sec²θ + csc²θ

Left side equals Right side so equation is verified

7 0

3 years ago