Answer:
If you look over the steps you can see that until 4x + x + 3 = 18, evertything is dandy. But the step after that 4x + x =21 seems a bit fishy.
Think about it they subtract 3 from both sides so the first side is correct
4x + x, but they added 3 to the other side:

not
4x+x = 21
Then we solve for 4x + x = 15

To solve for y we use :
y = x+3
y = 3+3 = 6
so (3,6) is the right answer
Option C is the right answer
½(12) = 6
½(64) = 32
½(30) = 15
½(78) = 39
Answer:The measure of angle RST is 120\°
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
m<RST=(6x+12)\° -----> equation A
m<RST=78\°+(3x-12)\° -----> equation B
equate equation A and equation B
(6x+12)\°=78\°+(3x-12)\°
Answer:
The correct option is;
c. Because the p-value of 0.1609 is greater than the significance level of 0.05, we fail to reject the null hypothesis. We conclude the data provide convincing evidence that the mean amount of juice in all the bottles filled that day does not differ from the target value of 275 milliliters.
Step-by-step explanation:
Here we have the values
μ = 275 mL
275.4
276.8
273.9
275
275.8
275.9
276.1
Sum = 1928.9
Mean (Average), = 275.5571429
Standard deviation, s = 0.921696159
We put the null hypothesis as H₀: μ₁ = μ₂
Therefore, the alternative becomes Hₐ: μ₁ ≠ μ₂
The t-test formula is as follows;

Plugging in the values, we have,
Test statistic = 1.599292
at 7 - 1 degrees of freedom and α = 0.05 = ±2.446912
Our p-value from the the test statistic = 0.1608723≈ 0.1609
Therefore since the p-value = 0.1609 > α = 0.05, we fail to reject our null hypothesis, hence the evidence suggests that the mean does not differ from 275 mL.
Answer:
70
Step-by-step explanation:
First, set up the ratio of c:t, which is 12:8. Then set up your new ratio of c:t, which is 105:?. The way I find the easiest is to divide 105 by 12, which is 8.75, then multiply that by 8, which is 70. To check if it's right, just divide 12 by 8, and 105 by 70, and if they're the same number, you've got it right.
Ps. I'm guessing you meant to ask the minimum number of trucks, not cars.