4 years ago

I need help asap!! pls

Mathematics

1 answer:

Nutka1998 [239]4 years ago

8 0

Sorry I need to see the top better

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Angle Measures and segment lengths. Find x.

Masja [62]

I hope this helps you

8^2=4.(4+x)

64=4.(4+x)

16=4+x

x=12

8 0

3 years ago

PLEASE explain this, I'm so lost. 25 points! What is the area of the base of the pyramid? Enter your answer in the box. Express

stepladder [879]

To find the area of the triangle shown we have to find the length of a and the base.

a can be found using the sine function. Recall sin = (opp)/(hyp)

Here $sin 60 = \frac{a}{8} 
$
$\frac{ \sqrt{3} }{2}= \frac{a}{8} 
$
$2a=8 \sqrt{3}$
$a=4 \sqrt{3}$

The base can be found using the sin of 30 degrees as this is a 30-60-90 right triangle.
$sin30= \frac{b}{8}$
$\ \frac{1}{2} = \frac{b}{8}$
$b=4$

The area of the triangle in the picture is given by $A=( \frac{1}{2} )bh= (\frac{1}{2})(4)( \frac{ \sqrt{3} }{2} )= \sqrt{3}$ .

The base of the pyramid is a hexagon which can be divided into 6 triangles each of which is double the area of the one we just found. So the area of the base = 2(area of the triangle we found)(6) = $12 \sqrt{3}$