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borishaifa [10]
3 years ago
11

Chen's report will take 8 1/3 hours to complete. He has worked 3/5 of that time doing research. How long has he worked?

Mathematics
2 answers:
Katarina [22]3 years ago
7 0
He has worked only 5 hours on his report 


Sergeu [11.5K]3 years ago
4 0
He has worked for 5 hours. 8 and 1/3 is equal to 24/3. Multiply that by 3/5 to get 75/15 which simplifies to 5.
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sveta [45]

Answer:

Step-by-step explanation:

From the given information, we can compute the table showing the summarized statistics of the two alloys A & B:

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Sample mean                    \bar {x} _A = 49.5      \bar {x} _B = 45.5

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Sample size                          n_A = 30        n_{B}= 30

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\mu_{\bar{X_1}-\bar{X_2}}= 49.5-45.5  \\ \\ = 4.0

Standard deviation of sampling distribution:

\sigma_{\bar{x_1}-\bar{x_2} }= \sqrt{\sigma^2_{\bar{x_1}-\bar{x_2} }} \\ \\ = \sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma^2_2}{n_2} } \\ \\ =\sqrt{\dfrac{25}{30}+\dfrac{25}{30}} \\\\=\sqrt{1.667}  \\ \\ =1.2909

Hypothesis testing.

Null hypothesis:  H_o: \mu_A -\mu_B = 0

Alternative hypothesis:  H_A:\mu_A -\mu_B > 4

The required probability is:

P(\overline X_A - \overline X_B>4|\mu_A - \mu_B) = P\Big (\dfrac{(\overline X_A - \overline X_B)-\mu_{X_A-X_B}}{\sigma_{\overline x_A -\overline x_B}} > \dfrac{4 - \mu_{X_A-\overline X_B}}{\sigma _{\overline x_A - \overline X_B}}   \Big) \\ \\ = P \Big( z > \dfrac{4-0}{1.2909}\Big) \\ \\ = P(z \ge 3.10)\\ \\ = 1 - P(z < 3.10) \\ \\ \text{Using EXCEL Function:} \\ \\  = 1 - [NORMDIST(3.10)]  \\ \\ = 1- 0.999032 \\ \\ 0.000968 \\ \\ \simeq  0.0010

This implies that a minimal chance of probability shows that the difference of 4 is not likely, provided that the two population means are the same.

b)

Since the P-value is very small which is lower than any level of significance.

Then, we reject H_o and conclude that there is enough evidence to fully support alloy A.

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3 years ago
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Answer:

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Let us first derive an equation for the productivity.

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