First, we are given that the inscribed angle of arc CB which is angle D is equal to 65°. This is half of the measure of the arc which is equal to the measure of the central angle, ∠O.
m∠O = 2 (65°) = 130°
Also, the measure of the angles where the tangent lines and the radii meet are equal to 90°. The sum of the measures of the angle of a quadrilateral ACOB is equal to 360°.
m∠O + m∠C + m∠B + m∠A = 360°
Substituting the known values,
130° + 90° + 90° + m∠A = 360°
The value of m∠A is equal to 50°.
<em>Answer: 50°</em>
Answer:
Step-by-step explanation:
How to Find Outliers Using the Interquartile Range(IQR)
Step 1: Find the IQR, Q1(25th percentile) and Q3(75th percentile). ...
Step 2: Multiply the IQR you found in Step 1 by 1.5: ...
Step 3: Add the amount you found in Step 2 to Q3 from Step 1: ...
Step 3: Subtract the amount you found in Step 2 from Q1 from Step 1:
Answer:
2/3 + 1/5 = 13/15
Step-by-step explanation:
C
6*3=18
6*8= 48 and 3*8=24
24*48= 1152
1152/18=64
5)
Equilateral triangle, all sides are equal
So 2x + 5 = 11
2x = 6
x = 3
Answer is the first one
3; Equilateral theorem
6)
Isosceles triangle has at least two congruent sides.
So 6x = 24
x = 4
Answer x = 4
Converse of the Base Angle Theorem
7)
5x + 7 = 52
5x = 45
x = 9
Answer
x = 9
Base angle theorem
8)
5y - 14 = 3y
2y = 14
y = 7
Answer
7; Equiangular theorem
