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wel
2 years ago
12

Mrs. Turner ran 2/4 miles around the track. Each lap is 4/8 of a mile. How many laps did she run?

Mathematics
2 answers:
Murrr4er [49]2 years ago
6 0

Answer:

2

Step-by-step explanation:

If shes running half of a mile, (2/4) than she ran 2 out of 4 laps

Sladkaya [172]2 years ago
5 0

Answer:

1

Step-by-step explanation:

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Hi can anyone please help me with some of these questions
sesenic [268]
The third picture is c=1
4 0
3 years ago
Circle T has diameters RP and QS. The measure of ∠RTQ is 12° less than the measure of ∠RTS. What is the measure of Arc Q P? 78°
Igoryamba

Answer:

RTQ+RTS=180

RTQ+12=RTS

2RTQ+12=180

RTQ=84

RTS=96

QTP=RTS=QP=96

6 0
3 years ago
If the average of x and y is 11 and the average of x, y and z is 5, what is the value of z? ​
mixer [17]

Answer:

z = -17

Step-by-step explanation:

If the average of x and y is 11, then;

x+y/2 = 11

x+y = 2 + 11

x+y = 22 .... 1

similarly, if average of x, y and z is 5, then;

x+y+z/3 = 5

x+y+z = 3*5

x+y+z = 15

Since x+y = 22

22 + z = 5

z  = 5 - 22

z = -17

Hence the value of z is -17

4 0
3 years ago
The frequency distribution shows the number of registered motor vehicles for a random sample of 200 California households.
erastovalidia [21]

Answer:

1). Mean = 2.275

2). Median = 2 vehicles

Step-by-step explanation:

From the given table,

Number of vehicles (x)         Frequency (f)      (f)×(x)             Cumulative freq.

                  0                                    11                  0                           11

                  1                                     52                52                        63

                  2                                    66                132                      129

                  3                                    35                105                      164

                  4                                    19                  76                       183

                  5                                    12                  60                       195

                  6                                     5                  30                       200

                                                                          \sum (f\times x) = 455

Number of households = 200

Mean = \sum \frac{f.x}{n}

          = \frac{455}{200}

         = 2.275

Median = value of \frac{(n+1)}{2}th observation

             = value of \frac{201}{2}th observation

             = Value of 100.5th observation

             = Since 100.5th observation lies in the row of cumulative freq. = 129

             = 2

Therefore, median number of registered vehicles per California household

= 2 vehicles

6 0
3 years ago
Someone help ples alk i need is the first two pleassss​
SashulF [63]
Table:

x values: 5, 10, 15, 20, 25

y values: 7, 14, 21, 28, 35
6 0
3 years ago
Read 2 more answers
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