The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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The type of triangle represented in the image attached to the task content is; Isosceles.
<h3>What type of triangle is triangle ABC?</h3>
By observation; since line AB and DE are parallel lines; it follows from the alternate Angie theorem that; <ABC = <BCE = 80°.
On this note, since angle ACD is 50°, the measure on <ACB is;
180 - 80 - 50 = 50°.
Therefore, since the sum of interior angle measures in a triangle is; 180°.
It follows that; <BAC is; 180 - 80 - 50 = 50°.
Hence, since the base angles; BAC and ACB are equal; it follows that the triangle in discuss is an isosceles triangle.
Read more on isosceles triangle;
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Answer: 350 square inches
The surface area formula of a trapezoidal prism is h (b + d) + l (a + b + c + d)
4(9+7) + 11 (5+7+9 +5)
--> 350