Answer:
P = 150 W * 60 sec/min * 60 min/hr = 540000 W-sec/hr
1 kW = 1000 W * 3600 sec = 3.6E6 W-sec
E (8 hrs) = 8 * .54E6 W-s = 4.32E6 W-sec
or E= 4.32/3.6 = 1.2 kW = .168 $/day
20/150 = .133 as much for a 20-watt bulb
For a LED bulb cost/day = .168 * .133 = $.022/da
Note 1 W = 1 Joule/sec
not really sure maybe 12
Answer: No
Step-by-step explanation: the ratio 3:6 reduces to one half
the ratio 6:3 reduces to 2 because division cannot be interchangeable
the answer is b bro
Step-by-step explanation:
102-8= 94
94/2= 47
Jiri is 47 years old.