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enot [183]
2 years ago
13

ASAP PLEASE! Please answer these 5 question! ONLY NEED ANSWERS! ANSWER ALL 5! NEEDS TO BE CORRECT!

Mathematics
1 answer:
4vir4ik [10]2 years ago
6 0
1. -32
2. 3/4
3. -3 3/8
4. -2 5/12
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classify each angle pair using all the names that apply using the diagram on the left , answering 1 2 3 4 and 5 , explain why.(
vredina [299]

Answer:

  see the attachment

Step-by-step explanation:

1.  Two angles that sum to 90° are <em>complementary</em>, whether they are adjacent or not. Angles LMN and NMP are also <em>adjacent</em>.

2.  Vertical angles created by two distinct lines are <em>never adjacent</em>. The sides of the angles are created by the same lines, and the angles share a vertex, but there is no ray that is a side common to both angles.

3.  Angle GMK is supplementary to angle JMG.

4.  Vertical angles are congruent. See question 2.

5.  See question 1.

6 0
3 years ago
Question 7.<br> identify the zeros of the graphed function<br> A) -2,2<br> B)-2,0,2<br> C)-2<br> D)2
photoshop1234 [79]

Answer:

-2,0 0,-8 , 2,0 hope that helps

7 0
3 years ago
Mrs. Byrne's class went raspberry picking. The data show the weights of the cartoons of raspberries the students picked. Make a
Licemer1 [7]
Here is what you tally chart/table would look like:

Weight     Tallies

1/4            lll
2/4            ll
3/4            lll
4/4            l


Here is what your line plot would look like:

X                     X
X          X         X 
<u>X          X         X         X
</u><u />1/4       2/4      3/4      4/4

4 0
3 years ago
Round 222702 to the nearest ten thousand
melomori [17]
220000 because 2 rounds down
4 0
2 years ago
Read 2 more answers
EMERGENCY PLEASE HELP STRUGGLING! The triangles in each pair are similar.
Ludmilka [50]

Answer: The missing length is 120 {option C}

Step-by-step explanation: What we have in the question is a triangle placed on top of another triangle and as shown in the attached diagram we can separate them into triangles BFC and GFH.

A close observation shows that line BC is parallel to line GH. Hence we have two similar triangles, and we can determine their similarity ratios as follows;

BF/FC = GF/FH

Similarly BF/BC = GF/GH

We can also express the following ratio

FC/FH = BC/GH

Therefore to calculate the missing side, which is GF, we can use the ratio

FC/FH = FB/FG

30/100 = 36/FG

By cross multiplication we now have 30 (FG) = 100 (36)

30FG = 3600

Divide both sides of the equation by 30

FG = 120

5 0
2 years ago
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