Answer:
The boy playing with football or any other game
Answer:
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Explanation:
The expression of the weight of the bar is given by,
W=mg
Here, g is the acceleration due to gravity
Substitute all the values
W=(18kg)(9.81m/s2)=176.58N
The expression of the angle θ
by using free body diagram is given by,
tanθ=ACBO+OC
Substitute all the values
tanθ=(1.3m)(1.2m)+(0.75m)θ=tan−1(1.31.95)θ=33.69∘
Take moment about point O and obtain the value of tension T.
∑MO=0Tsinθ×AC+W×(AO2cosθ1)−Tcosθ×CO=0
Substitute all the values
Tsin(33.69∘)×(0.75m)+(176.58N)×(1.5m2cos60∘)−Tcos(33.69∘)×(1.3m)=0T×0.416m+66.22N⋅m−T×1.081m=0−T×0.665m+66.22N⋅m=0T=−66.22N⋅m−0.665mT=99.58N
Hi lovely,
The answer you're looking for would be A) At first.
This would be the correct answer because if you took out any other words in the sentence it wouldn't make sense or it wouldn't be complete.
