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expeople1 [14]
2 years ago
6

Please HELP ME WITH THIS TY!

Mathematics
1 answer:
LenKa [72]2 years ago
7 0
X=117 degrees
Y = 63 degrees
Z = 117 degrees
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Please hurry!!!
algol [13]

Answer:

Gallons of punch used = 4.94 gallons

Step-by-step explanation:

Given that:

Liters of punch purchased = 25 liters

Liters of punch left over = 6 liters

Liters of punch used = 25 - 6 = 19 liters

According to the given statement;

1 liter = 0.26 gallons

19 liters = 0.26*19 gallons

19 liters = 4.94 gallons

Hence,

Gallons of punch used = 4.94 gallons

7 0
2 years ago
In the Hawaiian Beach Boy surf board vendor scenario, what if the fine was increased to $190 but the probability of a fine decre
zloy xaker [14]

Answer:

$190.50

Step-by-step explanation:

Expected value is the sum of each possible income multiplied by its probability.

There's a 5% chance that the vendor makes $200 and loses $190 (net gain of $10).

There's a 95% chance that the vendor makes $200 and loses $0 (net gain of $200).

So the expected value is:

Exp(RS) = $10 × 0.05 + $200 × 0.95

Exp(RS) = $190.50

5 0
3 years ago
Can anyone help me with this one please
bulgar [2K]
A. 314 sq cm

Explanation: pi•r^2
3.14 x 10^2
3.14 x 100 =314
7 0
2 years ago
Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that th
11111nata11111 [884]

Answer:

The null hypothesis is H_0: \mu = 14

The alternate hypothesis is H_a: \mu < 14

The test statistic is t = -1.95.

The p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

Step-by-step explanation:

Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that their highlighters could write continuously for 14 hours.

At the null hypothesis, we test if the mean is 14 hours, that is:

H_0: \mu = 14

At the alternate hypothesis, we test if the mean is less than 14 hours, that is:

H_a: \mu < 14

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

14 is tested at the null hypothesis:

This means that \mu = 14

X = 13.6 hours, s = 1.3 hours. Sample of 40:

In addition to the values of X and s given, we have that n = 40

Test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{13.6 - 14}{\frac{1.3}{\sqrt{40}}}

t = -1.95

The test statistic is t = -1.95.

P-value:

The p-value of the test is the probability of finding a sample mean lower than 13.6, which is a left tailed test, with t = -1.95 and 40 - 1 = 39 degrees of freedom.

Using a calculator, the p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

5 0
2 years ago
What is the surface area of this shape? 1cm 5cm 2cm 3cm 6cm 4cm
larisa86 [58]
88 square centimeters
6 0
2 years ago
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