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mario62 [17]
3 years ago
7

A box contains 2 red marbles, 3 green marbles, and 3 blue marbles. if we choose a marble, then another marble without putting th

e first one back in the box, what is the probability that the first marble will be green and the second will be blue?
Mathematics
2 answers:
Bad White [126]3 years ago
7 0
There are 7 marbles, including 3 green ones, so at the start, there is a 3/7 chance of getting a green marble.
Assuming you did get a green one, there are now 6 marbles left, with 2 blue marbles, so there is a 2/6 chance of taking a blue marble.
Given that both have to happen, you must multiply each probability, hence the total probability is 3/7 x 2/6, or a 1/7 chance.
Hope this helped
Zepler [3.9K]3 years ago
4 0

Answer:

The answer is actually 9/56

Step-by-step explanation:


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Answer:

10y3 - 5y2 - 10x + 4

 ————————————————————

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Step-by-step explanation:

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 

Step  2  :

Equation at the end of step  2  :

 

Step  3  :

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Simplify   ————————————————————

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Checking for a perfect cube :

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Final result :

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