A box contains 2 red marbles, 3 green marbles, and 3 blue marbles. if we choose a marble, then another marble without putting th

Question

mario62 [17]

4 years ago

7

A box contains 2 red marbles, 3 green marbles, and 3 blue marbles. if we choose a marble, then another marble without putting th

e first one back in the box, what is the probability that the first marble will be green and the second will be blue?

Mathematics

2 answers:

Bad White [126] · Answer 1 · 2022-02-05T14:18:53+03:00

There are 7 marbles, including 3 green ones, so at the start, there is a 3/7 chance of getting a green marble.
Assuming you did get a green one, there are now 6 marbles left, with 2 blue marbles, so there is a 2/6 chance of taking a blue marble.
Given that both have to happen, you must multiply each probability, hence the total probability is 3/7 x 2/6, or a 1/7 chance.
Hope this helped

Zepler [3.9K] · Answer 2 · 2022-02-05T16:21:31+03:00

Zepler [3.9K]4 years ago

4 0

Answer:

The answer is actually 9/56

Step-by-step explanation: