1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Liula [17]
3 years ago
13

LAST ATTEMPT IM MARKING AS BRAINLIEST!! (What is the circumference of the circle?)

Mathematics
1 answer:
aalyn [17]3 years ago
8 0

Use the pythagorean theorem a^2+b^2 = c^2 to plug in a = 8 and b = 6. You should find that the hypotenuse is c = 10. The diameter of the circle is 10 units, which leads to the circumference of C = 10\pi

<h3>Answer:  \boldsymbol{10\pi}</h3>
You might be interested in
A unicorn’s favorite food is marshmallows. They can find other food resources, but marshmallows are their absolute favorite. Usi
Tpy6a [65]

Answer:

69813.33 marshmallow

the calories required (i.e 10,920,800 ) is greater than the energy provided (i.e 7,500,000) hence the 2 unicorns cannot survive

Step-by-step explanation:

Given:

Unicorn weights = 440 kg

Marshmallow weighs = 0.5 grams

Unicorn needs = 34 calories/kg of body weight/day

Marshmallow offers = 3 calories/gram

Calories required by Unicorn in a week

= Calories needed × Weight of unicorn × Total days in a week

= 34 × 440 × 7

= 104,720 calories

Now,

Marshmallows required = \frac{\textup{Calories required}}{\textup{Energy offered by marshmallow}}

= \frac{\textup{104,720}}{\textup{3}}

= 34906.67 grams

Therefore,

the number of marshmallows required = \frac{\textup{Mass of marshmallow required}}{\textup{Mass of marshmallow}}

= \frac{\textup{34906.67}}{\textup{0.5}}

= 69813.33 marshmallow

b) Total calories provided by the marshmallow

= 5,000,000 × 0.5 × 3

= 7,500,000 calories

and,

calories required by 2 unicorns in an year

= weight of 2 unicorn × calories needed × number of days in an year

= 2 × 440 × 34 × 365

= 10,920,800

Since,

the calories required (i.e 10,920,800 ) is greater than the energy provided (i.e 7,500,000) hence the 2 unicorns cannot survive

5 0
4 years ago
Someone help please I can’t seem to get this one and its my last one
Bingel [31]

Answer:

345 cm squared I believe

I'm not 100% sure

4 0
3 years ago
Help I’m not sure with this one!! Urgent help
Nastasia [14]

This system has exactly one solution, because the two equation are linearly independent (i.e. one is not a multiple of the other).

We can explicitly find the solutions: from the first equation we deduce

x = \dfrac{c-by}{a}

Plug this value for x in the second equation:

\dfrac{a}{3}\cdot \dfrac{c-by}{a}+\dfrac{by}{2}=\dfrac{c}{6} \iff \dfrac{c-by}{3}+\dfrac{by}{2}=\dfrac{c}{6} \iff \dfrac{2(c-by)+3by}{6}=\dfrac{c}{6}

Multiply both sides by 6 to get

2(c-by)+3by=c \iff 2c-2by+3by=c \iff by=-c \iff y=-\dfrac{c}{b}

Plug this value for y in the expression for x:

x = \dfrac{c-by}{a} = \dfrac{c-b\cdot\frac{-c}{b}}{a}=\dfrac{2c}{a}

Since both a,b are not zero, both solutions are well defined.

8 0
3 years ago
at first the average mass some durians was 3.4kg.when 2 durians were added the aevrage mass of the 2 durians was 1.3kg was added
LekaFEV [45]

We conclude that the initial number of durians is 12.

<h3>How many durians were there at first?​</h3>

Let's say that initially, we had N durians, such that these N durians have an average mass of 3.4kg.

When 2 durians  (with an average mass of 1.3kg) more are added, the new average mass is given by:

(N*3.4kg + 2*1.3kg)/(N + 2)

And we know that the above amount is equal to 3.1kg, then we can write:

(N*3.4kg + 2*1.3kg)/(N + 2) = 3.1kg

Now we can solve this equation for N:

(N*3.4kg + 2.6kg) = 3.1kg*(N + 2)

N*(3.4kg - 3.1kg) = 6.2kg - 2.6kg

N*(0.3kg) = 3.6kg

N = (3.6kg)/(0.3kg) = 12

We conclude that the initial number of durians is 12.

If you want to learn more about mass:

brainly.com/question/1354972

#SPJ1

4 0
2 years ago
How can I find angle C?
VikaD [51]
Recall all interior angles in a triangle add up to 180°, therefore

\bf \stackrel{A}{x+40}~~+~~\stackrel{B}{2x-5}~~+~~\stackrel{C}{3x-17}~~=~~180&#10;\\\\\\&#10;6x+18=180\implies 6x=162\implies x=\cfrac{162}{6}
7 0
3 years ago
Other questions:
  • I need help on this
    6·1 answer
  • Can you finish this for me please? My calculator isn’t making sense and I’m sure I typed the equation in right. I will mark Brai
    11·2 answers
  • What is 64,000 X 46,000?
    13·2 answers
  • 2/3 - (30 divided by 5) + 9=
    10·2 answers
  • To change the number 4 into a fraction, what number goes in the denominator?
    15·2 answers
  • P(x)= P has degree 3 and zeros 5 and i.
    6·1 answer
  • Help plzzzzzzzzzzzzzzzzz
    13·1 answer
  • Find the length of PR
    9·2 answers
  • Simplify.<br> 3 1<br> 8 8<br> OA)<br> 2<br> 1<br> B)<br> 2<br> C)<br> OD)<br> 8
    14·2 answers
  • HELP Solve for x and y
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!