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kodGreya [7K]
2 years ago
9

· The solution set of a quadratic equation is{-1, 4). How many x-intercepts does the graph

Mathematics
1 answer:
Arlecino [84]2 years ago
8 0

Answer:

  • C. 2

Step-by-step explanation:

The solution set is {-1, 4}

<u>It means there are two solutions or two x-intercepts:</u>

  • (-1, 0) and (4, 0)

Correct choice is C

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Someone help please and please make sure it’s right :)
Anuta_ua [19.1K]

Answer:

11

Step-by-step explanation:

5x + 5 = 4x + 16 ( being alternate angles)

5x - 4x = 16 - 5

x = 11

Hope it will help :)

6 0
2 years ago
100/60 is exactly 1.66666666667. When I do long division my answer comes up as 1.6 with the decimal repeating, am I doing anythi
goblinko [34]

Answer:

I don't think you are doing anything wrong. Just ignore it and write the repeating decimal. If you're asked to do it, round it up instead.

5 0
3 years ago
Read 2 more answers
Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
What is k in this question<br> k/1.5 = 3
Reptile [31]

Answer:k equals 4.5

Step-by-step explanation: you multiply 1.5 times three

3 0
3 years ago
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It's going to be Lindsay's birthday soon, and her friends Sandy, Jay, and Hakeem have contributed equal amounts of money to buy
avanturin [10]
Each individual contributed $x
3x=$19.50
x=$6.50
Each friend contributed $6.50
5 0
3 years ago
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