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inn [45]
2 years ago
9

A person can pay $8 for a membership to the science museum and then go to the museum for just $1 per visit. What is the maximum

number of visits a member of the science museum can for a total cost of 44$
Mathematics
1 answer:
laila [671]2 years ago
5 0

The maximum number of visits for a member of science museum is 36.

Step-by-step explanation:

Given,

Membership fee = $8

Per visit fee = $1

Total cost = $44

Let,

x be the number of visits

y be the total cost

Total cost = per visit fee*number of visits + membership fee

y = x+8

44=x+8\\44-8=x\\36=x\\x=36

The maximum number of visits for a member of science museum is 36.

Keywords: variable, addition

Learn more about variables at:

  • brainly.com/question/12801884
  • brainly.com/question/12817595

#LearnwithBrainly

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Answer:

a) P(5

And we can find this probability with this difference:

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And using the norma standard distribution or excel we got:

P(-1.90

b) P(X>6) =P(Z> \frac{6-7.37}{1.25}) = P(Z>-1.096)

And using the complement rule we got:

P(Z>-1.096) =1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(7.37,1.25)  

Where \mu=7.37 and \sigma=1.25

We are interested on this probability

P(5

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(5

And we can find this probability with this difference:

P(-1.90

And using the norma standard distribution or excel we got:

P(-1.90

Part b

For this case we want this probability:

P(X>6)

And we can use the z score and we got:

P(X>6) =P(Z> \frac{6-7.37}{1.25}) = P(Z>-1.096)

And using the complement rule we got:

P(Z>-1.096) =1-P(Z

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It is known that 50% of adult workers have a high school diploma. If a random sample of 8 adult workers is selected, what is the
son4ous [18]

Answer:

85.56% probability that less than 6 of them have a high school diploma

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have a high school diploma, or they do not. The probability of an adult having a high school diploma is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

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P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

50% of adult workers have a high school diploma.

This means that p = 0.5

If a random sample of 8 adult workers is selected, what is the probability that less than 6 of them have a high school diploma

This is P(X < 6) when n = 8.

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{8,0}.(0.5)^{0}.(0.5)^{8} = 0.0039

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P(X = 2) = C_{8,2}.(0.5)^{2}.(0.5)^{6} = 0.1094

P(X = 3) = C_{8,3}.(0.5)^{3}.(0.5)^{5} = 0.2188

P(X = 4) = C_{8,4}.(0.5)^{4}.(0.5)^{4} = 0.2734

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85.56% probability that less than 6 of them have a high school diploma

7 0
3 years ago
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