the first two random numbers are 4,5.using linear congruential generator with a=4, m=11 and b=0 and 23 as the seed
linear congruential generator
Xn= an-+b Lm
0d s = 25 , b=6, YM 11, 024
Q O o m) 4, Lu) = 4x2%U)
m= 4x4j = 5 y-5
the numbers are 4, 5.
4.O0000 5.000TO
A linear congruence generator is an algorithm that returns a sequence of pseudorandom numbers computed using discontinuous piecewise linear equations. This method is one of the oldest and best-known pseudorandom number generator algorithms.
The linear congruential generator (LCG) is a pseudorandom number generator (PRNG ) is a class of algorithms. Random number generation plays an important role in many applications, from cryptography to Monte Carlo methods.
Learn more about linear congruential here: brainly.com/question/3168048
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The probability any one system works is 0.99
So the probability of any one system failing is 1-0.99 = 0.01, so basically a 1% chance of failure for any one system
Multiply out the value 0.01 with itself four times
0.01*0.01*0.01*0.01 = 0.000 000 01
I'm using spaces to make the number more readable
So the probability of all four systems failing is 0.00000001
Subtract this value from 1 to get
1 - 0.00000001 = 0.99999999
The answer is 0.99999999 which is what we'd expect. The probability of at least one of the systems working is very very close to 1 (aka 100%)
Answer:
-2.3
Step-by-step explanation: