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KIM [24]
4 years ago
12

Misha and Dontavious were asked to solve the following problem using linear programming. A local school district can operate a l

arge bus for $300 per day and a small bus for $200 per day. The district needs to arrange transportation for at least 360 students for a field trip and has enough chaperones to have one chaperone per bus for up to 7 buses. Each large bus can hold 60 students and each small bus can hold 45 students. What is the minimum cost for the transportation for the field trip?
Mathematics
2 answers:
bearhunter [10]4 years ago
4 0

Answer:

did you get the answer?

Step-by-step explanation:

AURORKA [14]4 years ago
4 0

Answer:

1700 for the bus

Step-by-step explanation:

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HELP ME PLEASE I WILL GIVE BRAINLIEST FOR BOTH PARTS PLEASE HELP
Katen [24]
For part A: two transformations will be used. First we will translate ABCD down 3 units: or the notation version for all (x,y) → (x, y - 3) so our new coordinates of ABCD will be:
A(-4,1)
B(-2,-1)
C(-2,-4)
D(-4,-2)

The second transformation will be to reflect across the 'y' axis. Or, the specific notation would be: for all (x,y) → (-x, y) New coordinates for A'B'C'D'
A'(4,1)
B'(2,-1)
C'(2,-4)
D'(4,-2)

Part B: The two figures are congruent.. We can see this a couple of different ways.
- first after performing the two transformations above, you will see that the original figure perfectly fits on top of the image.. exactly the same shape and size.
- alternatively, you can see that the original and image are both parallelograms with the same dimensions.
5 0
3 years ago
6x2 + 15x – 21<br> no clue
Gala2k [10]

Answer:

-303

Step-by-step explanation:

.............

7 0
3 years ago
A Tourist Information Center is between a Bus Station and a Train Station. When mapped on a grid, the Tourist Information Center
deff fn [24]

Given :

The Tourist Information Center is  located at (11,0) and the Bus Station is located at (-1,-10).

Also , Tourist Information Center is between a Bus Station and a Train Station.

To Find :

The point of location of train station .

Solution :

Let , point of location of train station is ( x,y ).

We know , mid-point of two points ( a, b) and ( c, d ) is given by :

(\dfrac{a+c}{2},\dfrac{b+d}{2}) .

Since , Tourist Information Center is between a Bus Station and a Train Station.

So , it is given by :

( 11 , 0 ) = (\dfrac{-1+x}{2},\dfrac{-10+y}{2})

Comparing both coordinate :

\dfrac{x-1}{2}=11\\\\x=22+1\\\\x=23

and

\dfrac{y-10}{2}=0\\\\y=10

Therefore , Train Station is located at point ( 23 , 10 ) .

Hence , this is the required solution .

3 0
3 years ago
Allen is buying a video that originally cost $49.He has a 10%-off coupon and will have to pay a 6% sales which expression will c
Gekata [30.6K]

Answer:

$46.746

Step-by-step explanation:

Allen is buying a video that originally cost = $ 49

Discount coupon = 10%

Sales tax= 6%

Hence, the price of video after discount coupon and sales tax= $ 49 ×\frac{100-10}{100}×\frac{100+6}{100}

Hence, the price of video after discount coupon and sales tax= $ 49 ×\frac{90}{100}×\frac{106}{100}

Price of video after discount coupon and sales tax= $ 49 × 0.9× 1.06

price of video after discount coupon and sales tax=  $46.746

Hence, the correct answer is $46.746

5 0
3 years ago
A particle, initially at rest, moves along the x-axis such that its acceleration at time t &gt; 0 is given by a(t) = 6cos(t). At
Rom4ik [11]

a. By the fundamental theorem of calculus, the velocity function is

v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du

The particle starts at rest, so v(0)=0, and we have

v(t)=\displaystyle\int_0^t6\cos u\,\mathrm du=6\sin u\bigg|_0^t=6\sin t

Then the position function is

x(t)=\displaystyle x(0)+\int_0^tv(u)\,\mathrm du

with x(0)=6, so

x(t)=6+\displaystyle\int_0^t6\sin u\,\mathrm du=6-6\cos u\bigg|_0^t=12-6\cos t

b. The particle is at rest whenever v(t)=0; this happens for

6\sin t=0\implies \sin t=0\implies t=n\pi

where n is any integer.

3 0
3 years ago
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