Answer:
x = -15/2
Step-by-step explanation:
For this problem, we will simply use equation properties to solve for x.
2x - 5 = -20
2x - 5 + 5 = -20 + 5
2x = -15 ( Add positive 5 to both sides )
2x * (1/2) = -15 * (1/2)
x = -15/2 ( Multiply both sides by 1/2)
Hence, the solution to x is -15 / 2.
Cheers.
Answer:
(x ÷ 8) + 23 – 4 = 36
x = 136
Step-by-step explanation:
Answer:
<em>Mrs. Adams will earn $3,120 of interest at the end of year 8.</em>
Step-by-step explanation:
<u>Simple Interest</u>
In simple interest, the money earns interest at a fixed rate, assuming no new money is coming in or out of the account.
We can calculate the interests earned by an investment of value A in a period of time t, at an interest rate r with the formula:

Mrs. Adams deposited an amount of A=$12,000 into an account that earns an annual simple interest rate of r=3.25%. We must find the interest earned in t=8 years. The interest rate is converted to decimal as:

The interest is then calculated:

Mrs. Adams will earn $3,120 of interest at the end of year 8.
Answer:
C.
Step-by-step explanation:
The bottom-right most cell tells us that the total number of students that responded to the survey is 310 students.
To find the answer, we can go through each choice.
A. Females taking Geometry
Row 1 Column 2 tells us that 53 females are taking geometry. 53/310 is about 17%.
B. Females taking Algebra II.
Row 1 Colume 3 tells us that 62 females are taking Algebra II. 62/310 is 20%.
C. Males taking Geometry.
Row 2 Colume 2 tells us that 59 males are taking Geometry. 59/310 is about 19%. Choice C is correct.
D. Males taking Algebra I.
44 out of the total 310 respondents are male and is taking Algebra I. 44/310 is about 14%.
Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:

- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of 660, hence
.
- The standard deviation is of 90, hence
.
- A sample of 100 is taken, hence
.
The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

By the Central Limit Theorem



has a p-value of 0.8665.
1 - 0.8665 = 0.1335.
0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213