4) a. x+y=1–(1)
y=2x-8—(2)
(2) into (1)
x+(2x-8)=1
3x-8=1
3x=1+8
x=9/3
x=3—(3)
(3) into (2)
y=2(3)-8
y=-2
ans x=3, y=-2
b. x+y=19—(1)
y=5x+1—(2)
(2) into (1)
x+(5x+1)=19
6x+1=19
6x=19-1
x=18/6
x=3—(3)
(3) into (2)
y=5(3)+1
y=16
ans x=3, y=16
c.x+y=-2—(1)
y=x-10—(2)
(2) into (1)
x+(x-10)=-2
2x-10=-2
2x=-2+10
x=8/2
x=4–(3)
(3) into (2)
y=4-10
y=-6
ans x=4, y=-6
5) 3x=y—(1)
x=y-16–(2)
(2) into (1)
3(y-16)=y
3y-48=y
2y=48
y=48/2
y=24–(3)
(3) into (2)
x=24-16
x=8
ans x=8, y=24
For the answer to the question above asking to<span> write an expression to model its age in dog years</span><span> for a dog that is 2 years old or older. If x is equal to human age
then the dog is 2 years older
X = human years
x + 2 = is for the dog age
</span>
Answer:
C. The meeting will be in Los Angeles California on July, 17.
Step-by-step explanation:
This doesn't use commas correctly because there should be a comma after Los Angeles because it is a location. Also, there should not be a comma after 17 because the comma goes after the date when the year is included, which it is not.
The ratio depicts that their is 63 boys and 16 girls based on the ratio 7:4.
I hope this helps!
Working on x and y first, we get:
<span><span><span>x6 / </span><span>x3</span></span>= <span>x3</span></span> and
<span><span><span>y6/ </span><span>y12 </span></span>= 1/ <span>y6</span></span> so, we have:<span><span> 2 <span>x3 / </span></span><span>y6
Entering values in original equation, we get:
</span></span><span>(2 <span>x3/ </span><span>y6</span><span>)^2</span></span>=4 x^6 / y^12
