Hey there!
If z = 5
we replace "z" with "5"
So, let's test out the problem to see if it is true or false
Problem becomes:
![3(5) = 2(5) + 5](https://tex.z-dn.net/?f=3%285%29%20%3D%202%285%29%20%2B%205%20)
Let's work this out
![3(5) = 15](https://tex.z-dn.net/?f=3%285%29%20%3D%2015%20)
Problem becomes:
![15 = 2(5) + 5](https://tex.z-dn.net/?f=15%20%3D%202%285%29%20%2B%205)
![2(5) = 10](https://tex.z-dn.net/?f=2%285%29%20%3D%2010%20)
Problem becomes:
![15 = 10 + 5](https://tex.z-dn.net/?f=15%20%3D%2010%20%2B%205%20)
![10 + 5 = 15](https://tex.z-dn.net/?f=10%20%2B%205%20%3D%2015%20)
So, therefore it looks like this statement/ sentence is
![True](https://tex.z-dn.net/?f=True)
!
~
Okay so for number 3, you have to do the top work first.
3: POSITIVE 2!! first, you do the stuff inside the parentheses first because of P(parentheses)EMDAS. so, 14-2-10! -2-10 is -12 and then plus positive 14 is +2. but, the negative sign outside of the parentheses makes that +2 a -2.
but, you cant forget the -12 outside. you have to do -12-2 which gets you -14. then, this is easy! -14 divided by -7 is a positive 2!
5: POSITIVE 3!! again, do the stuff in the parentheses first!! -2-4 is -6. then, -6 x 2 is -12! so, divide -12 by -4 and you get a positive 3!
It has no solutions. Hope it helps
Answer:
7-2x=3+x
Step-by-step explanation:
where x is the number