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Radda [10]
3 years ago
6

What are other ways i can get 626

Mathematics
1 answer:
nadezda [96]3 years ago
5 0

Answer:

there is no question

Step-by-step explanation:

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A theater can hold 120 giants or 144 elves. If 90 giants are already inside, how many elves can also be admitted?
navik [9.2K]

Answer:

36

Step-by-step explanation:

make proportion giants to elves

120/144 = 90/x cross multiply

120x =144*90

120x =12960 divide by 120

x = 108

so if there are 90 giants in the theater there are  108 elves also

considering that total 144 elves can be  in the theater subtract 144 and 108 so 36 more elves can be admitted

3 0
3 years ago
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a radio is being dis coounted 20%. If the sale price of the raido is 51.44$, what was the original price
natulia [17]
51.44÷80%=64. 3$$
Because (100-20=80%)
6 0
3 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 149 millimeters,
Artemon [7]

Answer:

The probability that the sample mean would differ from the population mean by more than 0.5 millimeters is 0.2420.

Step-by-step explanation:

Let <em>X</em> = the diameter of the steel bolts manufactured by the steel bolts manufacturing company Thompson and Thompson.

The mean diameter of the bolts is:

<em>μ</em> = 149 mm.

The standard deviation of the diameter of bolts is:

<em>σ</em> = 5 mm.

A random sample, of size <em>n</em> = 49, of steel bolts are selected.

The population of the diameter of bolts is not known.

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

The mean of the sampling distribution of sample mean is:

\mu_{\bar x}=\mu=149\ mm

The standard deviation of the sampling distribution of sample mean is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5}{\sqrt{49}}=0.7143

Compute the probability that the sample mean would differ from the population mean by more than 0.5 millimeters as follows:

P(\bar X>\bar x)=P(\frac{\bar X-\mu_{\bar x}}{\sigma _{\bar x}}>\frac{0.50}{0.7143})\\=P(Z>0.70)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 0.5 millimeters is 0.2420.

8 0
4 years ago
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lys-0071 [83]

It will last for 6 days

8 0
3 years ago
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Help pls !! the 2 are the same theyre just duplicated !
meriva

Answer: 1.Non 2.Pro 3.Non 4.Pro 5.Non 6.Non 7.Pro 8.Pro 9.Non 10.Pro

Step-by-step explanation:

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