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3 years ago

A theater can hold 120 giants or 144 elves. If 90 giants are already inside, how many elves can also be admitted?

Mathematics

2 answers:

EastWind [94]3 years ago

6 0

Answer:

36 elves

Step-by-step explanation:

Using proportions

We have space for 30 more giants

30 giants x elves

------------- = ----------

120 full 144 elves full

Using cross products

30*144 = x*120

Divide each side by 120

30*144/120 = 120x/120

36 = x

We can have 36 elves

navik [9.2K]3 years ago

3 0

Answer:

Step-by-step explanation:

make proportion giants to elves

120/144 = 90/x cross multiply

120x =144*90

120x =12960 divide by 120

x = 108

so if there are 90 giants in the theater there are 108 elves also

considering that total 144 elves can be in the theater subtract 144 and 108 so 36 more elves can be admitted

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Choose the correct simplification of x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4t

Umnica [9.8K]

Answer:

<h3>The option A) $x^{10}z^7$ is correct answer.</h3><h3>The correct simplification for the given expression $\frac{x^{12}\times z^{11}}{x^2\times z^4}$ is $x^{10}z^7$ </h3>

Step-by-step explanation:

Given expression is x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4th power.

The given expression can be written as $\frac{x^{12}\times z^{11}}{x^2\times z^4}$

<h3>To choose the correct simplification of the given expression :</h3>

Now we have to simplify the given expression as below

$\frac{x^{12}\times z^{11}}{x^2\times z^4}$

$=x^{12}\times z^{11}(x^{-2}\times z^{-4})$ ( by using the identity $\frac{1}{a^m}=a^{-m}$ )

$=(x^{12}.x^{-2})\times (z^{11}.z^{-4})$

$=x^{12-2}\times z^{11-4}$ ( by using the identity $a^m.a^n=a^{m+n}$ )

$=x^{10}\times z^7$

$=x^{10}z^7$

∴ $\frac{x^{12}\times z^{11}}{x^2\times z^4}=x^{10}z^7$

<h3>The correct simplification for the given expression $\frac{x^{12}\times z^{11}}{x^2\times z^4}$ is $x^{10}z^7$ </h3><h3>Hence option A) $x^{10}z^7$ is correct answer.</h3>

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3 years ago

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Step-by-step explanation:

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