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Gekata [30.6K]
3 years ago
9

A theater can hold 120 giants or 144 elves. If 90 giants are already inside, how many elves can also be admitted?

Mathematics
2 answers:
EastWind [94]3 years ago
6 0

Answer:

36 elves

Step-by-step explanation:

Using proportions

We have space for 30 more giants

30 giants     x elves

------------- = ----------

120  full      144 elves  full

Using cross products

30*144 = x*120

Divide each side by 120

30*144/120 = 120x/120

36 = x

We can have 36 elves

navik [9.2K]3 years ago
3 0

Answer:

36

Step-by-step explanation:

make proportion giants to elves

120/144 = 90/x cross multiply

120x =144*90

120x =12960 divide by 120

x = 108

so if there are 90 giants in the theater there are  108 elves also

considering that total 144 elves can be  in the theater subtract 144 and 108 so 36 more elves can be admitted

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Answer:

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Step-by-step explanation:

LCM - Lowest Common Factors

HCF - Highest Common Factors

____________________________________________________________

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Factors of 123 - 1, 3, 41, 123

So now we know the factors of 15, 42, 123 what is lowest and highest factor we can find in every number

____________________________________________________________

I have bolded the lowest and highest common factor.

Factors of 15 - 1, 3, 5, 15

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Factors of 123 - 1, 3, 41, 123

_______________________________________________

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HCF - 3

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Step-by-step explanation:

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