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elixir [45]
2 years ago
10

Factor Completely. 2a(x+y)+b(x+y)

Mathematics
2 answers:
8_murik_8 [283]2 years ago
7 0

Answer:

2a(x+y)+b(x+y) = (x+y)(2a+b)

sertanlavr [38]2 years ago
7 0

Let's simplify step-by-step.

2a(x+y)+b(x+y)

Distribute:

=(2a)(x)+(2a)(y)+(b)(x)+(b)(y)

=2ax+2ay+bx+by

<h2>Answer:</h2><h2>=2ax+2ay+bx+by</h2>

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Gustavo is in a contest where he will win one of four possible
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Answer:

Step-by-step explanation:

One of four in number form is 1/4 this is the only thing I can tell you without knowing what the answer choices are or what the question is

3 0
3 years ago
If an object dropped from the height of 144 ft the function h(t)=-16t^2+144 gives the height of the object after t seconds. When
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3 seconds
0= -16t^2+144
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4 years ago
Callie was billed $416.48 for car repairs. She will pay the service center in 4 equal monthly installments from her bank account
ryzh [129]

Answer:

$104.12

Step-By-Step Explanation:

First divide $416.48 by 4 ↓

                                         $416.48÷4= $104.12

Callie will have $104.12 less than what she earned each month once you take away the money she is paying for car repairs.

3 0
3 years ago
Rewrite each expression as a polynomial in standard form: x^2-5x+6 ÷ x-3 + x^3-1 ÷ x-1
iragen [17]

Answer:

So in standard form equation will be x^2+2x-1

Step-by-step explanation:

We have given expression \frac{x^2-5x+6}{x-3}+\frac{x^3-1}{x-1}

Let first we solve first part of the expression

So \frac{x^2-5x+6}{x-3}=\frac{x^2-3x-2x+6}{x-3}=\frac{(x-3)(x-2)}{x-3}=x-2

Now second part \frac{x^3-1}{x-1}

We know the algebraic identity a^3-b^3=(a-b)(a^2+ab+b^2)

So by using this identity

\frac{x^3-1}{x-1}=\frac{(x-1)(x^2+x+1)}{x-1}=x^2+x+1

Now adding first and second part

x-2+x^2+x+1=x^2+2x-1

So in standard form equation will be x^2+2x-1

4 0
3 years ago
Can someone helpppp
Dmitry [639]
Yes, I can help what would you like me to do
5 0
3 years ago
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