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3 years ago

How do you write 2/5 as a percentage

Mathematics

2 answers:

dusya [7]3 years ago

7 0

Step-by-step explanation:

Explanation:

To get 25 as a percent, we need the denominator to be 100 .

Now that we have a denominator equal to 100 , just look at the numerator and that's your percent.

40%

.40.

.4 or 0.4.

Flauer [41]3 years ago

6 0

Answer:

40%

Step-by-step explanation:

To convert a decimal to a fraction, multiply it to 100

$\frac{2}{5} \times 100$

$=\frac{2}{5} \times \frac{100}{1}$

$=\frac{2\times100}{5\times1}$

$=\frac{200}{5}$

$=40$

Therefore, $\frac{2}{5}$ is 40%

You might be interested in

A recipe for a batch of 3 dozen chocolate chip cookies calls for 3 cups of flour, one cup of sugar, and 2 cups of chocolate chip

BaLLatris [955]

Answer:

2 cups of flour

2/3 cup of sugar

1 1/3 cups of chocolate chips

Step-by-step explanation:

3 dozen chocolate chip cookies

3 cups of flour

1 cup of sugar

2 cups of chocolate chips

The recipe is for 3 dozen cookies as stated above.

If you make 2 dozen cookies, then you are making 2/3 of the recipe since 2 is 2/3 of 3.

That means you need 2/3 of all the ingredients.

2/3 × 3 dozen chocolate chip cookies

2/3 × 3 cups of flour

2/3 × 1 cup of sugar

2/3 × 2 cups of chocolate chips

We simplify the amounts to:

2 dozen chocolate chip cookies

2 cups of flour

2/3 cup of sugar

1 1/3 cups of chocolate chips

3 0

3 years ago

mayam bought potato chips to school she share 1/4 of her chips with friends and 1/8 of her chips with her teacher how many has s

nika2105 [10]

$\huge\underline\mathtt\colorbox{cyan}{3/8}$

$\huge\mathsf\colorbox{white}{}$

<h2>Step-by-step explanation :</h2>

Total shared part:

1/4 + 1/8

Taking LCM and adding:

2/8+1/8

Adding gives:

3/8

4 0

3 years ago

I dont want you to answer question for me, i have already answered it as shown in the picture. I want you to let me know if i ha

Mashutka [201]

Answer:

$\begin{equation}
\sqrt{3}-1,2 \sqrt{10} \div 5, \sqrt{14}, 3 \sqrt{2}, \sqrt{19}+1,6
\end{equation}$

Explanation:

Given the irrational numbers:

$3 \sqrt{2}, \sqrt{3}-1, \sqrt{19}+1,6$, $2 \sqrt{10} \div 5,\sqrt{14}$

In order to arrange the numbers from the least to the greatest, we convert each number into its decimal equivalent.

$\begin{gathered} 3\sqrt{2}=3\times1.414\approx4.242 \\ \sqrt{3}-1\approx1.732-1=0.732 \\ \sqrt{19}+1\approx4.3589+1=5.3589 \\ 6=6 \\ 2\sqrt{10}\div5=2(3.1623)\div5=1.2649 \\ \sqrt{14}=3.7147 \end{gathered}$

Finally, sort these numbers in ascending order..

$\begin{gathered} \sqrt{3}-1\approx1.732-1=0.732 \\ 2\sqrt{10}\div5=2(3.1623)\div5=1.2649 \\ \sqrt{14}=3.7147 \\ 3\sqrt{2}=3\times1.414\approx4.242 \\ \sqrt{19}+1\approx4.3589+1=5.3589 \\ 6=6 \end{gathered}$

The given numbers in ascending order is:

$\begin{equation}
\sqrt{3}-1,2 \sqrt{10} \div 5, \sqrt{14}, 3 \sqrt{2}, \sqrt{19}+1,6
\end{equation}$

Note: In your solution, you can make the conversion of each irrational begin on a new line.

8 0

1 year ago

What is 3+3-2? The problems are getting harder. :(

liq [111]

Answer:

Order of Operations is what you have to use

8 0

4 years ago

Read 2 more answers

Volumes I to IV of "Famous Mathematicians" are sitting in numerical order between two bookends on a table. Each cover of a volum

Rama09 [41]

We want to find the distance between the first page of the first book in a collection and the last page of that collection.

We will get that the distance is 13cm

Let's see how to solve this:

Each cover is 0.5cm thick
The pages (all of them) for each volume are 5cm thick.

We want to find the distance between the first page of the first volume and the last page of the last volume.

Because we go from the first page of the first volume to the last page of the last volume, we <u>will ignore the first cover and pages of the first volume and the pages and back cover of the last volume</u>.

We ignore the pages because in normal book positioning, the first page will be on the right side of the book (and the last page is on the left side), and if we order the books from left to right, then we can ignore all the other pages of book I and book IV.

Then we have:

one cover for volume 1.
two covers and pages for volume 2
two covers and pages for volume 3
one cover for volume 4.

Now we just need to add all the correspondent measures:

( 0.5cm) + (5cm + 2*0.5cm) + (5cm + 2*0.5cm) + ( 0.5cm) = 13cm

Then the distance between the page 1 of volume I and last page of volume IV is 13cm.

If you want to learn more, you can read:

brainly.com/question/12082741

3 0

2 years ago