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3 years ago

Write an equation of the line in point-slope form that passes through the given points.

Mathematics

1 answer:

RSB [31]3 years ago

5 0

Answer:

Step-by-step explanation:

point - slope formula: y - y1 = m(x-x1)

we need to find the slope ... or what is m ?

m = rise / run

m = y2 - y1 / x2 - x1

where the given points are (x1,y1) and (x2,y2)

m= 7-5 / 6-5

m = 2 / 1

m =2

now use either point and plug the slope and the point into the point-slope formula

y-5 =2(x-5) :)

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Really need help please! Brainliest to correct!

vovikov84 [41]

Let's say "m" is the manufactoring cost per drill (in dollars).

Then the manufactorer sells it for $4 more, so this would be:

m+4

Then the chain store sells it for 140% of the price is paid the manufactorer, so this would be "140% of (m+4)" which translates to "1.4•(m+4)" or more simply:

1.4(m+4)

P(m) = 1.4(m+4), where m is the initial manufactoring cost (in dollars).

Simplifying, you could rewrite this as:

P(m) = 1.4m + 5.6

7 0

3 years ago

If f(x) = + 8, what is f(x) when x = 10?<br> Help

Reptile [31]

Step-by-step explanation:

f(x) = + 8

x = 10?

f(10)= +8

no change

5 0

3 years ago

Read 2 more answers

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers: