We use unitary method over here. To find out the number pages he writes in 1 hour we should;
16÷8 = 2.
So Brennan writes 2 pages in 1 hour.
Hence, in 10 hours he writes;
2 × 10 = 20.
∴ in ten hours Brennan writes 20 pages.
D: 89 is the prime number.
Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10
Total friends = 10
Friends from kindergarten = 4
Probability is the chance that a given event will occur. Probability of an event lies within 0 to 1
P(E) = Favourable outcomes / Total outcomes
Probability of getting 1st friend from kindergarten = 4/10
Probability of getting 2nd friend from kindergarten = 3/9
Probability of getting 3rd friend not from kindergarten = 6/8
Since all these probabilities are independent, We can use Multiplicative identity. Thus,
Required probability is 4/10 * 3/9 * 6/8
= 1/10
Thus, Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10
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