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2 years ago

Edward can run mile in 300 seconds. What is Edward's unit rate?

Mathematics

1 answer:

Yakvenalex [24]2 years ago

5 0

Answer:

b im not sure

Step-by-step explanation:

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Please help its urgent

hram777 [196]

Answer:

<h2>Function is y = x.</h2><h2>Domain: $-3 \leq x \leq 2$ .</h2><h2>Range: $-5 \leq y \leq 4$ .</h2>

Step-by-step explanation:

In the given image, the line passes through (-1, -1) and (1, 1).

Let the equation of the line is $y = mx + c$ , where m is the tangent of the line and c is a constant.

Putting the co-ordinates of the points in the equation, we get $-1 = -m + c$ and $1 = m + c$

From the two equations we get, c = 0 and m = 1.

Hence, the function is y = x.

Domain is $-3 \leq x \leq 2$ .

Range is $-5 \leq y \leq 4$

5 0

3 years ago

Suppose that g(x) = f(x + 8) + 4. Which statement best compares the graph of g(x) with the graph of f(x)?

UNO [17]

The graph of g(x) is the same as that of f(x), EXCEPT that the graph of f(x) has been translated 8 units to the left and 4 units up.

4 0

3 years ago

I do not see the mistake. Can someone please help me find it?

nikdorinn [45]

3rd one ( not 20 characters so ASHWDHWHEIUCNEJEIH)

4 0

3 years ago

Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4) Erik said, "The right-hand side is factored, so I'll use the zer

Mumz [18]

Answer:

C) Both

Step-by-step explanation:

The given equation is:

$0=(3x+2)(x-4)$

To solve the given equation, we can use the Zero Product Property according to which if the product <em>A.B = 0</em>, then either A = 0 OR B = 0.

Using this property:

$(3x+2) = 0 \Rightarrow \bold{x = -\frac{2}{3}}\\(x-4) = 0 \Rightarrow \bold{x = 4}$

So, Erik's solution strategy would work.

Now, let us discuss about Caleb's solution strategy:

Multiply $(3x+2)(x-4)$ i.e. $3x^2-12x+2x-8$ = $3x^2-10x-8$

So, the equation becomes:

$0=3x^2-10x-8$

Comparing this equation to standard quadratic equation:

$ax^2+bx+c=0$

a = 3, b = -10, c = -8

So, this can be solved using the quadratic formula.

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\times3 \times (-8)}}{2\times 3}\\x=\dfrac{-(-10)\pm\sqrt{196}}{6}\\x=\dfrac{10\pm14}{6} \\\Rightarrow x= 4, -\dfrac{2}{3}$