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2 years ago

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.

Mathematics

1 answer:

Mariulka [41]2 years ago

4 0

Answer:

The answer is 55 6/9, but when simplified, it is 55 1/3

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The value of the solid's surface area is equal to the value of the solid's volume. Find the value of x. We know the length is 9

Lerok [7]

Given:

The value of the solid's surface area is equal to the value of the solid's volume.

Length(l) = 9 units

width(b) = 4 units

Height(h) = x units

To find:

The value of x.

Solution:

Solid's surface area is

$Area=2(lb+bh+hl)$

$Area=2(9\times 4+4\times x+x\times 9)$

$Area=2(36+4x+9x)$

$Area=2(36+13x)$

$Area=72+26x$

Volume of solid is

$Volume=l\times b\times h$

$Volume=9\times 4\times x$

$Volume=36x$

Solid's surface area = Volume of solid

$72+26x=36x$

$72=36x-26x$

$72=10x$

Divide both sides by 10.

$7.2=x$

Therefore, the value of x is 7.2.

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2 years ago

On a 28-question test, there are 2-point questions, 4-point questions, and 5-point questions. The test is worth a total of

SashulF [63]

The answer to this problem is 8

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1 year ago

I need to find x pls

Rainbow [258]

I hope this helps you

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2 years ago

I need help ASAP please

Vilka [71]

Answer:A -3,6

Step-by-step explanation: Substitue the answers in and they work out

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2 years ago

A rectangular parking lot must have a perimeter of 440 feet and an area of at least 8000 square feet. Describe the possible leng

tangare [24]

Answer:

The possible parking lengths are 45.96 feet and 174.031 feet

Step-by-step explanation:

Let x be the length of rectangular plot and y be the breadth of rectangular plot

A rectangular parking lot must have a perimeter of 440 feet

Perimeter of rectangular plot =2(l+b)=2(x+y)=440

2(x+y)=440

x+y=220

y=220-x

We are also given that an area of at least 8000 square feet.

So, $xy \leq 8000$

So, $x(220-x) \leq 8000$

$220x-x^2 \leq 8000$

So, $220x-x^2 = 8000\\-x^2+220x-8000=0$

General quadratic equation : $ax^2+bx+c=0$

Formula : $x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-220 \pm \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=\frac{-220 + \sqrt{220^2-4(-1)(-8000)}}{2(-1)} , \frac{-220 - \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=45.96,174.031$

So, The possible parking lengths are 45.96 feet and 174.031 feet

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2 years ago