The histogram is attached. Every column shows on the bottom the range of age and on the left the number of cars of that particular age.
In order to find the percentage of cars with less than 20 years or more than 40 years, you have to sum up the numbers of cars in the first two columns from left (age 0-9 and 10-19) and the last two (age 40-49 and 50-59).
The number of cars of requested age is: 3 + 2 + 0 + 3 = 8
Now, you need to calculate the total number of cars (sum the cars of every column): 3 + 2 + 8 + 4 + 0 + 3 = 20
Lastly, you need to calculate the ration between the cars of requested age and the total number of cars, and transform it into a percentage:
8 ÷ 20 = 0.40 = 40%
Therefore, your answer is
40%.
V = 4/3πr³
V = 4/3(3.14)(14)³
V = 4/3(3.14)(2744)
V = 4/3(8616.16)
V = 11488.21333cm³
Answer:
141
Step-by-step explanation:
141
It is asking you to slice off 40% of the bounce height in each subsequent bounce.
So you start with full height 1, that's n = 0 bounces. Then after n = 1 bounce the new height is .6. After the second bounce, n = 2, the height becomes .6 X .6 = .36. And after n = 3, we have .6 X .6 X .6 = .216
So by induction we see that h(n = 5) = .6^n = .6^5 = 0.07776 = .078 of its original height or H = .078*200 = 15.6 ft. after five bounces. ANS. 16.0 if rounded to the nearest tenth
:)
33 × 2 = 66
66 + 33 = 99
Total cost would be $99