Answer:
.Graph f(x) = 6x + 2 and g(x) = 6x - 4. Then describe the transformation from the graph of f(x) to the graph of g(x). у 6. 5. 4. 3. 2 . 0 1 A -3 -2 -1 3 2 -i - 5 4 5 6 -3 ### 5. -6
Step-by-step explanation:
.Graph f(x) = 6x + 2 and g(x) = 6x - 4. Then describe the transformation from the graph of f(x) to the graph of g(x). у 6. 5. 4. 3. 2 . 0 1 A -3 -2 -1 3 2 -i - 5 4 5 6 -3 ### 5. -6
The interquartile range (IQR) is 15.
To find the IQR, you must:
1) Find the median
2) Split the data set in two at the median.
3) Find the medians from both the groups you made in Step 2
4) Label the smaller one Quartile 1 and the larger one Quartile 3 (Hint: The median is Quartile 2)
5) Subtract: Quartile 3 - Quartile 1
Answer:
Maximum area = 800 square feet.
Step-by-step explanation:
In the figure attached,
Rectangle is showing width = x ft and the side towards garage is not to be fenced.
Length of the fence has been given as 80 ft.
Therefore, length of the fence = Sum of all three sides of the rectangle to be fenced
80 = x + x + y
80 = 2x + y
y = (80 - 2x)
Now area of the rectangle A = xy
Or function that represents the area of the rectangle is,
A(x) = x(80 - 2x)
A(x) = 80x - 2x²
To find the maximum area we will take the derivative of the function with respect to x and equate it to zero.

= 80 - 4x
A'(x) = 80 - 4x = 0
4x = 80
x = 
x = 20
Therefore, for x = 20 ft area of the rectangular patio will be maximum.
A(20) = 80×(20) - 2×(20)²
= 1600 - 800
= 800 square feet
Maximum area of the patio is 800 square feet.
Your answer is =<span>x+<span>277</span></span>