-7 2/3 + (-5 1/2) + 8 3/4=

Sum of equal angles is 360<br> 1/3x+(x-20)+40+(x-10)

kicyunya [14]

x = 150 did this help you?

6 0

3 years ago

A rectangular yard measuring 39 ft by 67 ft is bordered (and surrounded) by a fence. Inside, a walk that is 4 ft wide goes all t

Gekata [30.6K]

The area of the walk is 784 square feet

Area is the quantity that expresses the extent of a region on the plane or on a curved surface

First, calculate the area of the rectangular yard.

Area = L x W

where A equals area, L equals length, and W equals width.

According to the stated problem:

A = 39 x 67

A = 2613 square feet <-------Area of Rectangular yard.

Now, according to the stated problem there is a walk that is 4 feet wide going all the way along the fence (Inside). "

Therefore, we have 8 feet to subtract from each of the values above (39) and (67).

That is 4 feet on each side,

A = L x W

A = 31 x 59

A = 1829 square feet <----------Area of new rectangle formed by allowing for three foot walk.

Now, subtract the area of the new rectangle formed from the area of the original area. Doing so, will give you the area of the walk, correct?

Original area = 2613 square feet

New area = 1829 square feet

Hence, the Area of WALK = 784 square feet

Learn more about area on: brainly.com/question/22972014

#SPJ1

3 0

1 year ago

HELP PLEASE HURRY... 65 POINTS

stepan [7]

B is the answer to your question I remember putting that in my other class

3 0

3 years ago

Read 2 more answers

Someone please help me

yuradex [85]

Answer:

112in²

Step-by-step explanation:

Formulas: V = $\frac{lwh}{3}$ , V = lwh

Sub: v = $\frac{4 x 4 x 6}{3}$

Solve: 32

Sub: v = 4 x 4 x 5

Solve: 80

V = 80 + 32

V = 112

<u>The total volume of the figure is 112in²</u>

3 0

2 years ago

50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle

aalyn [17]

Answer:

$EF=4\sqrt{3}$

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

$A_{\text{rect}}=8(6)=48\text{ cm}^2$

The area of the triangle is 1/4 of this. Therefore:

$\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2$

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

$\displaystyle 12=\frac{1}{2}(DE)(DF)$

Since DE = DF:

$24=DF^2$

Thus:

$DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE$

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

$(DE)^2+(DF)^2=(EF)^2$

Therefore:

$(2\sqrt6)^2+(2\sqrt6)^2=EF^2$

Square:

$24+24=EF^2$

Add:

$EF^2=48$

And finally, we can take the square root of both sides:

$EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}$

6 0

3 years ago

Read 2 more answers