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2 years ago

What is the measure of angle x? Enter your answer in the box. M

Mathematics

2 answers:

tiny-mole [99]2 years ago

8 0

Answer:

Step-by-step explanation:

82+37=119. 180-119=61. remember triangles always add up to 180°

STatiana [176]2 years ago

8 0

Answer:

I am pretty sure it's 61

Step-by-step explanation:

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3 years ago

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3 years ago

Subtract 15 and 4 , double the difference, and then add two-thirds

mrs_skeptik [129]

15-4 = 11

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3 years ago

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Find the measure of the the sides of DEF then classify it by it sides. <br> D(8,-6) E(-1,-3) F(-2,5)

Mama L [17]

Answer:

Part a) The measure of the sides of triangle DEF are

$d_D_E=\sqrt{90}\ units$

$d_E_F=\sqrt{65}\ units$

$d_D_F=\sqrt{221}\ units$

Part b) Is a scalene triangle

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have the coordinates

D(8,-6) E(-1,-3) F(-2,5)

step 1

Find the length side DE

D(8,-6) E(-1,-3)

substitute in the formula

$d=\sqrt{(-3+6)^{2}+(-1-8)^{2}}$

$d=\sqrt{(3)^{2}+(9)^{2}}$

$d_D_E=\sqrt{90}\ units$

step 2

Find the length side EF

E(-1,-3) F(-2,5)

substitute in the formula

$d=\sqrt{(5+3)^{2}+(-2+1)^{2}}$

$d=\sqrt{(8)^{2}+(-1)^{2}}$

$d_E_F=\sqrt{65}\ units$

step 3

Find the length side DF

D(8,-6) F(-2,5)

substitute in the formula

$d=\sqrt{(5+6)^{2}+(-2-8)^{2}}$

$d=\sqrt{(11)^{2}+(-10)^{2}}$

$d_D_F=\sqrt{221}\ units$

step 4

Classify the triangle by the measure of its sides

we have

$d_D_E=\sqrt{90}\ units$

$d_E_F=\sqrt{65}\ units$

$d_D_F=\sqrt{221}\ units$

Is a scalene triangle, because is a triangle in which all three sides have different lengths.

6 0

3 years ago

If x+1/x = 5 find the value of x^3 +1/x^3. pls solve

Korolek [52]

Answer:

1) solve x+1/x = 5

$\frac{x + 1}{x} = 5$

$x + 1 = 5x$

$x - 5x = - 1$

$- 4x = - 1$

$x = \frac{ -1}{ - 4}$

$x = \frac{1}{4}$

2) solve x³+1/x³

$x {}^{3} + \frac{1}{x {}^{3} }$

substitute x = 1/4 into the expression

$( \frac{1}{4} ) {}^{3} + \frac{1}{( \frac{1}{4}) {}^{3} }$

$\frac{1}{64} + \frac{1}{ \frac{1}{64} }$

$\frac{1}{64} + \frac{64 \times 1}{1}$

$\frac{1}{64} + 64$

$\frac{4097}{64} \: or \: 64.02$

5 0

3 years ago