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max2010maxim [7]
2 years ago
5

In casting experiments performed using a certain alloy.

SAT
1 answer:
jeyben [28]2 years ago
7 0
Answer:
A) Cm = 2.232 s/mm²
B) Time taken to solidify = 74.3 seconds
Explanation:
(A) Since a side is 50mm and all sides of a cube are equal, thus, Volume of the cube is;V = 50 x 50 x 50 = 125,000 mm³
There are 6 faces of the cube, thus Surface Area A = 6 x (50 x 50) = 15,000 mm²
So, Volume/Area = (V/A) = 125,000/15,000 = 8.333 mm
Cm is given by the formula; Cm =[Tts] /(V/A)² where Tts is time taken to solidify and it's 155 seconds in the question. Thus;
Cm = 155/(8.333)²= 2.232 s/mm²
(B) For;Cylindrical casting with D = 30 mm and L = 50 mm.;
Volume of cylinder is;
V = (πD²L) /4
So,V = (π x 30² x 50)/4 = 35,343mm³
Surface area of cylinder is;
A = (2πD²)/4 + (πDL)
Thus, A = ((π x 30²)/2) + (π x 30 x 50) = 6126 mm²
Volume/Area is;
V/A = 35,343/6126 = 5.77 mm
Same alloy and mold type was hsed as in a above, thus, Cm is still 2.232 s/mm²
Since Cm =[Tts] /(V/A)²
Making Tts the subject, we have;
Tts =Cm x (V/A)²
Tts = 2.232 x (5.77)² = 74.3 seconds
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<h3>Plessy v. Ferguson case.</h3>

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Which of the following is a true statement about diffusion.
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D) Molecules move from areas of high concentration to areas of low concentration.

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A high school track coach has just purchased a new stopwatch that has an uncertainty of s. runners on the team regularly complet
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A high school track coach has just purchased a new stopwatch. The stopwatch manual states that the stopwatch has an uncertainty of ±0.05 s . Runners on the track coach’s team regularly clock 100-m sprints of 11.49 s to 15.01 s . At the school’s last track meet, the first-place sprinter came in at 12.04 s and the second-place sprinter came in at 12.07 s .

No, the new stop watch will not be effective in timing the sprint team. The reason for the same is that the uncertainty in the stopwatch is too small to effectively differentiate between the sprint times.

If sprinters were timed with the new stopwatch, first sprinter's time would have been between =  12.04 - 0.05  and 12.04 + 0.05

                                  = 11.99 and 12.09

or between the interval [11.99 , 12.09]

while the second sprinter's time would have been between

= 12.07 - 0.05 =and 12.07 + 0.05

= 12.02  and 12.12

or between the interval [12.0.2 , 12.12]

Hence, there is an overlap between the worst time of the first sprinter, that is, 11.99 and the best time of the second sprinter, that is, 12.02

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Paradichlorobenzene, c6h4cl2 c 6 h 4 c l 2 , is a component of mothballs. A solution of 2. 00 g g in 22. 5 g g of cyclohexane bo
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The value of kb of cyclohexane in the given question is; kb = 2.82 °C/m

<h3>Understanding Molality of a Solution</h3>

Molality of solution = (Number of moles of C₆H₄Cl₂)/(Mass of Cyclohexane)

Now;

Number of moles of C₆H₄Cl₂ = Mass/molar mass = 2g/147 g/mol

Number of moles of C₆H₄Cl₂ = 0.0136 mol

Molality of solution = 0.0136/(22.5 * 10⁻³ kg)

Molality of solution = 0.6 m

Now, to find kb for cyclohexane, we will use the formula;

T_b(solution) - T_b(solvent) = kb × molality of solution

Thus;

82.39 - 70 = kb * 0.6

kb = (82.39 - 70)/0.6

kb = 2.82 °C/m

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