Hey can you please help me for research about dogs??????????????

SAT

1 answer:

Ronch [10]3 years ago

3 0

Answer:

ofc

Research:

This website has perfect answers on anything you need to know abt dogs ^^

https://studymoose.com/dog

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If f(x)=(x+3)³+4<br> let g(x)=f(x+1)-2<br> find when g(x)=12

Alla [95]

Answer:

Explanation:

g(x) = f(x + 1) - 2

g(x) = (x + 1 + 3)^3 -2

g(x) = (x + 4)^3 - 2

Now what are we supposed to do with this? I'm guessing we are to find what value of x will make g(x) = 12. If I'm wrong, leave a note in the form of a comment.

g(x) = 12

(x + 4)^3 - 2 = 12 Add 2 to both sides.

(x + 4)^3 = 14 Take the cube root of both sides.

x + 4 = cubrt(14)

x + 4 = 2.4101 Subtract 4

x = 2.4101 - 4

x = -1.5899

8 0

2 years ago

Please help.

belka [17]

Answer:positively cheap labour.

Then negatively Low taxes

Explanation:because it's of low level school people or drop outs who don't mind much of wages as compared to office related work or jobs

Then low taxes as a result of favour being imposed on the cheap kabour

4 0

3 years ago

Read 2 more answers

Soon Yi loves to bake, and she is making flaky pastry. Soon Yi starts with a layer of dough 222 millimeters (\text{mm})(mm)left

frozen [14]

Answer:

3 times

Explanation:

When the dough is folded, it increases by a constant factor. We can model the growth of the thickness using the exponential growth model

$T(n)=T_0(1+r)^n$

Where:

Initial thickness, $T_0$ = 2mm

Growth factor, r =8%=0.08

We want to find the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm.

i.e When $T(n)\geq 2.5$ mm$

$2(1+0.08)^n\geq 2.5\\2(1.08)^n\geq 2.5\\$Divide both sides by 2$\\\dfrac{2(1.08)^n}{2}\geq \dfrac{2.5}{2}\\\\1.08^n\geq 1.25\\\\$Change to logarithm form\\n \geq \log_{1.08}1.25\\\\n\geq \dfrac{\log 1.25}{\log 1.08} \\\\n\geq 2.9$