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AURORKA [14]
2 years ago
8

Please help me !! pls pls pls

Mathematics
1 answer:
frutty [35]2 years ago
6 0

Answer:

aas congruence postulate

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What does this mean?
boyakko [2]

Answer:

Its the symbol "pi" which is 3.14

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3 years ago
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The standard deviation of the data set is 2.3. Compute the variance to the nearest hundredth. 2,2,2,3,5,5,6,7,8
Arada [10]
The standard deviation is the square root of the variance...so that means the variance is the standard deviation squared.

2.3^2 = 5.29 <===
7 0
3 years ago
Select the equivalent expression.
Vanyuwa [196]

For this case we must find an expression equivalent to:(y ^ 3 * 2 ^ 5) ^ 2

By definition of power properties we have to meet:

(a ^ n) ^ m = a ^ {n * m}

So, rewriting the expression we have:

y^{3 * 2} * 2^ {5 * 2} =\\y^ 6 * 2^{10}

Answer:

Option B

y^6*2^{10}

4 0
3 years ago
An 8-foot ramp needs to be elevated at an angle measuring 10° to be level with a step. Approximately how far
emmainna [20.7K]

Answer:

Approximately 7.9 feet.

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cos 10 = x / 8     where x is the required distance.

x = 8 cos 10

= 7.878 feet.

3 0
3 years ago
A manager of a grocery store wants to determine if consumers are spending more than the national average. The national average i
strojnjashka [21]

The valid conclusions for the manager based on the considered test is given by: Option

<h3>When do we perform one sample z-test?</h3>

One sample z-test is performed if the sample size is large enough (n  > 30) and we want to know if the sample comes from the specific population.

For this case, we're specified that:

  • Population mean = \mu = $150
  • Population standard deviation = \sigma = $30.20
  • Sample mean = \overline{x} = $160
  • Sample size = n = 40 > 30
  • Level of significance = \alpha = 2.5% = 0.025
  • We want to determine if the average customer spends more in his store than the national average.

Forming hypotheses:

  • Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get: H_0: \mu_0 \leq \mu = 150
  • Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically H_1: \mu_0 > \mu = 150

where \mu_0 is the hypothesized population mean of the money his customer spends in his store.

The z-test statistic we get is:

z = \dfrac{\overline{x} - \mu_0}{\sigma/\sqrt{n}} = \dfrac{160 - 150}{30.20/\sqrt{40}} \approx 2.094

The test is single tailed, (right tailed).

The critical value of z at level of significance 0.025 is 1.96

Since we've got 2.904 > 1.96, so we reject the null hypothesis.

(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).

Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.

Learn more about one-sample z-test here:

brainly.com/question/21477856

3 0
1 year ago
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