2 years ago

Please help me !! pls pls pls

1 answer:

6 0

Answer:

aas congruence postulate

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anzhelika [568]

Answer:

$log_e^{67.21}= a$

Step-by-step explanation:

The equation is ,

$\implies 67.21 = e^a$

Here e is the Euler's Number . The log which are defined on the base e are called Natural logarithms.

Say if we have a expoteintial equation ,

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Similarly our required answer will be ,

$\implies\boxed{ log_e^{67.21}= a }$

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