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2 years ago

If $180 is invested at an interest rate of 7% per year and is compounded weekly, how

Mathematics

1 answer:

Rufina [12.5K]2 years ago

3 0

Answer:

$405.4

Step-by-step explanation:

$A= P(1+\frac{r}{100}) ^{n}$

-->180*(1+7/100)^12

-->$405.4

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Please help! :)

Volgvan

Answer:

So the correct option is First one

i.e $\dfrac{9\pi}{A}=\dfrac{90}{360}$

Step-by-step explanation:

Given:

Area of Shaded part = 9 π square feet

To Find :

Area of Circle = ?

Solution:

90 degree center angle is equivalent to an area of 9 Π square feet

So, 360 degree center is equivalent to area A which is the area of the complete circle.

So the Ratio will be

$\dfrac{90}{9\pi} =\dfrac{360}{A}$

Setting the given statements in proportion:

$\dfrac{90}{9\pi} =\dfrac{360}{A}$

On solving we get the required

$\dfrac{9\pi}{A} =\dfrac{90}{360}$

So the correct option is First one

i.e $\dfrac{9\pi}{A}=\dfrac{90}{360}$

Alternate Method:

Shaded part is of 90°

Area of Shaded part = 9 π square feet

And Full Circle is of 360° that is 4 sector of 90°

$\textrm{Area of Circle}=4\times (Shaded\ part)$

$\textrm{Area of Circle}=4\times 9\pi$

$\textrm{Area of Circle}=36\pi$

So the correct option is First one

i.e $\dfrac{9\pi}{A}=\dfrac{90}{360}$

On solving this we get

$A=36\pi\ feet^{2}$

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Montano1993 [528]

Answer:

JK = 30 .

Step-by-step explanation:

As JMLK is a kite the diagonals bisect each other at right angles so triangle JNK is a right triangle.

JK^2 = 18^2 + 24^2 = 900

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If a 50 ft flagpole casts a 95 ft shadow, then how long is the shadow that a 5 ft tall of man casts ?

lesantik [10]

9.5 feet,to find that you must find out how many times longer the shadow of the pole is than the pole, and to do that you must divide 95 by 50, in which you get 1.9. And then to find the length of the shadow the man casts you must multiply his height by 1.9.

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3 years ago