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Alina [70]
3 years ago
13

PLEASE HELP ASAP WILL GIVE BRAINLIES

Mathematics
1 answer:
Lisa [10]3 years ago
8 0

Answer:

<em><u>17: 480</u></em>

(We first arrange all of the candidates except b in a line. This can be done in 5! ways. We now add b to the line. Since we now want to count the arrangements where b is positioned next to a, there are two possibilities for the position of b. (Either left of a or right of a).

There are thus 2⋅5! ways of arranging the candidates so that a and b are next to each other, and hence 6!−2⋅5!=4⋅5!=480 ways of arranging the candidates so that a and b are not next to each other)

<u><em>18</em><em>:</em></u><em><u> </u></em>i don't know sorry

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