Question

I dont understand this problem

Answer 1

Answer:

D and F

Step-by-step explanation:

$x^{2}+4x+4=12$ can be rewritten as $x^{2} +4x-8=0$.

From there you can use the quadratic formula $x=\frac{-b±\sqrt{b^{2}+4ac } }{2a}$ (ignore the A, I can‘t seem to remove it), where a=1, b=4, and c=-8.

$x=\frac{-4±\sqrt{4^{2}-4(1)(-8)} }{2(1)}$

Then you get $x=\frac{-4±\sqrt{16+32}}{2}$

Then you get $x=\frac{-4±\sqrt{48} }{2}$

So $x=-2±\frac{4\sqrt{3} }{2}$

Which means $x=-2+2\sqrt{3}$ or $-2-2\sqrt{3}$ which are choices D and F.