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3 years ago

HOW DO U COMBINE LIKE TERMS in math?? DO NOT LOOK IT UP :) THX

Mathematics

1 answer:

gayaneshka [121]3 years ago

6 0

Answer:

See below

Step-by-step explanation:

"Like terms" are terms with the same variable or exponents.

You can add or subtract these just like you would with regular numbers.

Examples:

2x + 4x = 6x

5xy + 7xy = 12xy

6 $x^{2}$ + 5 $x^{2}$ = 11 $x^{2}$

Let me know if you need more examples or have any questions :)

You might be interested in

Prove the following statement. Assume that all sets are subsets of a universal set U.

nadezda [96]

Answer:

O U ⊆ A ∪ B True

O U ⊆ A ∩ B False

O A ∪ B ⊆ U True

O B ⊆ U True

O A ⊆ U True

O A ∩ B ⊆ U True

Step-by-step explanation:

To prove the first part

$\text{If} \,\,\,\,\,\, A^{c} \subseteq B \,\,\,\,\,\text{then} \,\,\,\,\, A \cup B = U$

Remember that any set is a subset of the universal set. Therefore it is true that

$A \cup B \subseteq U$

Now, given any $x \in U$ it is true that

$x \in B \,\,\,\, \text{or} \,\,\,\, x \notin B$

Now according to the information given initially

$\text{If} \,\,\,\,\, x \notin B \,\,\,\,\, \text{then} \,\,\,\,\, x \notin A^{c}$

And then you know that

$\text{If} \,\,\,\,\, x \notin A^{c} \,\,\,\,\,\text{then} \,\,\,\,\,\,\, x \in A$

Therefore $U \subseteq A \cup B$ and using double inclusion

$U = A \cup B$ .

Now using the information just exposed

O U ⊆ A ∪ B True

O U ⊆ A ∩ B False

O A ∪ B ⊆ U True

O B ⊆ U True

O A ⊆ U True

O A ∩ B ⊆ U True

4 0

3 years ago

Find f(x) of |2x-2| if x is -1.

Pavlova-9 [17]

Answer:

Step-by-step explanation:

x = -1

|2x-2| = |2(-1)-2| = |-2-2| = |-4| = 4

4 0

3 years ago

Read 2 more answers

HELP

dybincka [34]

Answer:

y=2×+1 im a bit rusty hope this helps in some way

8 0

3 years ago

What measurement is equivalent to 6 kilograms?

Anna007 [38]

Answer:

6000 g

Step-by-step explanation:

In the metric system, 6 kg = 6000 g. (The prefix kilo- means 1000.)

In other units of measurement, 6 kg ≈ 13.2277357311 pounds. This is not an exact conversion.

4 0

4 years ago

Which integral gives the area of the region in the first quadrant bounded by the graphs of y2 = x − 1, x = 0, y = 0, and y = 2?

Zarrin [17]

Interesting that only integrals along the $x$ -axis are suggested when integrating along the $y$ -axis would be much simpler... Anyway, you have to split the interval of integration into two. The "height" of the region is not uniform over the entire interval.

When $y=0$ , we have $0^2=x-1\implies x=1$ . When $y=2$ , we have $2^2=x-1\implies x=5$ . Then the area we want is given by

$\displaystyle\int_0^12\,\mathrm dx+\int_1^52-\sqrt{x-1}\,\mathrm dx$

which seems to agree with the last option.

5 0

3 years ago