Answer:
Yes, we can assume that the percent of female athletes graduating from the University of Colorado is less than 67%.
Step-by-step explanation:
We need to find p-value first:
z statistic = (p⁻ - p0) / √[p0 x (1 - p0) / n]
p⁻ = X / n = 21 / 38 = 0.5526316
the alternate hypothesis states that p-value must be under the normal curve, i.e. the percent of female athletes graduating remains at 67%
H1: p < 0.67
z = (0.5526316 - 0.67) / √[0.67 x (1 - 0.67) / 38] = -0.1173684 / 0.076278575
z = -1.538681
using a p-value calculator for z = -1.538681, confidence level of 5%
p-value = .062024, not significant
Since p-value is not significant, we must reject the alternate hypothesis and retain the null hypothesis.
1 thousand and 1 hundred means 1100.
In scientific notation, it's 1.1*10^3
Answer:
Step-by-step explanation:
80 over 100*150
80 divided by 100=0.8 *150=1208student
0.8 *60=48
645/560=1.151785714
Ther perccent error in her estimate is 15%
Answer:
Sam worked 
hours that day (fractional answer)
Step-by-step explanation:
The total number of hours Sam worked is the sum of all the three hours given.
Let's add the first 2 using LCM and then add that result with the last.
Firstly:
Now,
The hours worked by Sam is 41/30 hours (fractional answer).
