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liq [111]
2 years ago
10

A worker was just hit by a forklift the scene is safe and you begin to assess the worker you see that she is conscious and breat

hing normally but obviously in pain what’s is the purpose of doing a secondary survey on this victim
Advanced Placement (AP)
1 answer:
Fiesta28 [93]2 years ago
5 0

The purpose of doing a secondary survey on this victim is to: Look for any potentially life threatening injuries.

<h3>What is secondary survey?</h3>

Secondary survey are body survey carried out on a victim so as to detect any form of life threatening injuries and this survey is carried out by examining the whole body of the victim.

Life-threatening injuries are injuries that can lead to death if not diagnosed and treated.

Based on the information given carrying out secondary survey on this victim as the victim may have apparent injury.

Hence, secondary survey is important as it will help to detect any  life threatening injuries that may not be immediately visible.

Example of  life-threatening injuries includes:

  • Head injury
  • Skull fractures
  • Neck injury
  • Spinal cord injury etc

Inconclusion the purpose of doing a secondary survey on this victim is to: Look for any potentially life threatening injuries.

Learn more about secondary survey here:brainly.com/question/1695365

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If the wait time is less than 30 minutes for 75% of all patients in the emergency room, what is the probability that the
Greeley [361]

The probability that the proportion of patients who wait less than 30 minutes is 0.582 or less is 0.0020

<h3>What is probability? </h3>

Probability can be defined as the likelihood of an event to occur. In statistics, the mean of the sample distribution typically shows the probability of the population.

From the parameters given:

  • The sample size (n) = 55 patients
  • Let's assume that the mean (x) = 32 (i.e. 58.2%) of the patients

The sample proportion \mathbf{\hat p} can be computed by using the expression:

\mathbf{\hat p = \dfrac{x}{n}}

\mathbf{\hat p = \dfrac{32}{55}}

\mathbf{\hat p =0.582}

If the percentage of the probability of all patients in the emergency room = 0.75

The probability that the proportion of patients who wait less than 30 minutes is 0.582 or less can be computed as:

\mathbf{( \hat P \leq 0.582) = P \Big( \dfrac{\hat p - p}{\sqrt{\dfrac{p(1-p)}{n}}} \leq \dfrac{0.582 - 0.75}{\sqrt{\dfrac{0.75(1-0.75)}{55}}} \Big )}

\mathbf{( \hat P \leq 0.582 )= P \Big( Z \leq \dfrac{-0.168}{\sqrt{0.003409}} \Big )}

\mathbf{( \hat P \leq 0.582) = P \Big( Z \leq -2.88 \Big )}

From the Z distribution table:

\mathbf{( \hat P \leq 0.582) = 0.00198}

\mathbf{( \hat P \leq 0.582) \simeq 0.0020}

Learn more about probability here:

brainly.com/question/24756209

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