Answer:
y = - 8
Step-by-step explanation:
y - 16 - 3y = 0
Group like terms
y - 3y - 16 = 0
Add similar elements: y - 3y = - 2y
- 2y - 16 = 0
Add 16 to both sides
- 2y - 16 + 16 = 0 + 16
Simplify
- 2y = 16
Divide both sides by - 2
= 
Simplify : y
Apply the fraction rule: 
= 
Divide the numbers: 
= y
Simplify : - 8
Apply the fraction rule:
Divide the numbers: 
= 8
= - 8
y = - 8
Answer:
L= A/WH
Step-by-step explanation:
Off topic Btw it reminds me of area = length * width/height
Answer:
A. 2(8)+2(w)=26
B. 16+2w=26
Subtract 16 from both sides of the equation
2w=10
Divide both side by 2
The width is 5
Step-by-step explanation:
Answer:
x<−31
Step-by-step explanation:
<h3>Given</h3>
1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.
2) Regular pentagon PENTA with side lengths 9 m
<h3>Find</h3>
The area of each figure, rounded to the nearest integer
<h3>Solution</h3>
1) The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².
