When graphing the inequality y ≤ 2x − 4, the boundary line needs to be graphed first. Which graph correctly shows the boundary l
1 answer:
Answer:
See Below
Step-by-step explanation:
The boundary line follows the graph of y = 2x - 4 because it represents the line of maximum or minimum values the graph could take. y = 2x - 4 has a y-intercept of -4 because it is in slope-intercept form. It also has a slope of 2, so to find another point on the line, you can go up two and right one. Also, this inequality has a solid line because it is "less than or equal to" and a solid line represents the values that equal.
You might be interested in
If you graph the end points C and D then graph the 4 points at the end it is difficult to tell which points are on CD without a line.
Using the endpoints find the slope (change in y/ change in x) then substitute a point in to find the intercept.
Slope = (-6-4)/(6- -8) = -5/7
Intercept equation (-6) = -5/7 (6) + b
b = -1.71428571429
Graphing the line shows only 2 points on the line (–2.75, 0.25) and <span>(0.75, –2.25)
I am confused by the part, "</span><span>P is the length of the line segment from D". Were you given a length P to help you determine which point. Using the distance formula to find the length from each point to D doesn't help determine which one is best with the information you have given. The image shows the distances I calculated and the graphed points.
I hope this helps!</span>
Using the endpoints find the slope (change in y/ change in x) then substitute a point in to find the intercept.
Slope = (-6-4)/(6- -8) = -5/7
Intercept equation (-6) = -5/7 (6) + b
b = -1.71428571429
Graphing the line shows only 2 points on the line (–2.75, 0.25) and <span>(0.75, –2.25)
I am confused by the part, "</span><span>P is the length of the line segment from D". Were you given a length P to help you determine which point. Using the distance formula to find the length from each point to D doesn't help determine which one is best with the information you have given. The image shows the distances I calculated and the graphed points.
I hope this helps!</span>