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Gemiola [76]
2 years ago
11

HELP ME PLEASE ( BRAINIEST) NO LINKS thank you..10 points

Mathematics
1 answer:
alexira [117]2 years ago
7 0

Answer:

Can't see the question

Step-by-step explanation:

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Simplify the following expression using only positive exponents. Help please!? It has to be only positive exponents the -9/7t an
wlad13 [49]
(-9t^25) / (7t^26) = -9 / (7t)

8 0
3 years ago
What is the number in the middle of 1.5 and7.1
amm1812
Add the numbers together and divide it by 2. 1.5 + 7.1 is 8.6. Then divide by 2 to get 4.3
4 0
3 years ago
Read 2 more answers
Witch set of orderd pairs contains only points that are on the graph of the function y=12-3x
anygoal [31]
You can try then by plotting the points in. 
The answer is C

Make sure by plotting in the points, lets take (-5,27)
y = 12 -3(-5)
y = 12 + 15
y = 27
27 = 27
This is correct 

Lets try (-1,15)
y = 12 -3(-1)
y = 12 + 3 
y = 15 
15 = 15
This is correct 

Lets try (8,-12)
y = 12 -3(8)
y = 12 - 24 
y = -12 
-12 = -12
This is correct too. 

The correct ordered pairs are <span>C(-5,27),(-1,15),(8,-12)</span>
5 0
3 years ago
Please need help I will be MARKING as BRIANILIST. thank you so much. ​​
ryzh [129]

Answer:

C

Step-by-step explanation:

I am guessing that's it.

8 0
3 years ago
Read 2 more answers
What lump sum do parents need to deposit in an account earning 9%, compounded monthly, so that it will grow to $100,000 for thei
gogolik [260]

Answer:

They need to deposit $31,172.49

Step-by-step explanation:

The compound interest formula is given by:

A = P(1 + \frac{r}{n})^{nt}

Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time the money is invested or borrowed for, in years.

In this problem

We want to find P for which A = 100000 when r = 0.09, n = 12, t = 13

So

A = P(1 + \frac{r}{n})^{nt}

100000 = P(1 + \frac{0.09}{12})^{12*13}

3.208P = 100000

P = \frac{100000}{3.208}

P = 31172.49

They need to deposit $31,172.49

6 0
4 years ago
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