HELP HURRY PLS

Micah can do 75 push up in 3 minutes Edward Lowe can do 130 push-ups in 5 minutes are these rates equivalent

IrinaK [193]

No because Edward can do 26 push-ups per minute while Micah can only do 25 push-ups per minute

6 0

3 years ago

An object launched straight up at a speed of 29.4 meters per second has a height, h, in meters of h , t seconds after the object

Nostrana [21]

Answer:

h = 44.06 meters (maximum height)

the time the object takes to complete this whole path is 6 seconds, this is why the time at which the object reaches its maximum height will between 0 and 6 seconds

Step-by-step explanation:

To solve this question, we need to first recognize that this is a constant acceleration problem, specifically, it can be thought of as a projectile motion problem.

Recall, the equations of motion:

$1) v^2 - v_0^2 = 2a(s - s_0)\\2) s = v_0^2 + \frac{1}{2} at^2\\3) v = v_0 + at$

What do we already know?

$v_0 = 29.4 ms^-1$
The launch is straight up
$a = -9.81 ms^-2$ this is the gravitational acceleration $g$

$s_0 = 0 m$ , since our reference point is at s = 0, (the ground)

We can use use the Eq(1):

we know that when any object is launched up, at maximum height its velocity is going to be zero, $v = 0 ms^-2$

$v^2 - v_0^2 = 2a(s - s_0)\\0^2 - (29.4)^2 = 2(-9.81)(s- 0)\\s = 44.06 m$

this is the maximum height!

Why does t have to between zero and six?

We can answer this using a bit visualization, if you think about the second equation

$s = v_0 t - \frac{1}{2}at^2\\ s = 29.4t - 4.905t^2$

this is the equation of the whole trajectory that object makes.

and if you solve this by making $s = 0$ , you will get the times at which the object was at the ground. the times will be 0s and 5.99s.

so the amount of time the object takes to go through this whole path is 6 seconds and this why the object will only reach its maximum height in between this time interval.

hope this helps :)

5 0

3 years ago

Two birds sit at the top of two different trees. The distance between the first bed and a birdwatcher on the ground is 34 feet t

stira [4]

Answer:

Step-by-step explanation:

The given triangle is a right angle triangle.

The distance between the first bed and the bird watcher on the ground represents the opposite side of the right angle triangle.

The distance between the birdwatcher and the second bird is 47 feet. This represents the hypotenuse of the right angle triangle. To determine the angle of depression, x degrees, we would apply the Sine trigonometric ratio which is expressed as

Sin θ = opposite side/hypotenuse

Sin x = 34/47 = 0.723

x = Sin^-1(0.723)

x = 46.3 degrees to the nearest tenth.

5 0

3 years ago

Read 2 more answers

The supplement of an angle is 50 less than 3 times its complement, find the measure of the angle

Lelechka [254]

Answer:

$20^{\circ}$ .

Step-by-step explanation:

Two angles are supplements of one another if their sum is $180^{\circ}$ .

Two angles are complements of one another if their sum is $90^{\circ}$ .

Let $x^{\circ}$ be the measure of the angle in question.

The supplement of this angle would be $(180 - x)^{\circ}$ .

The complement of this angle would be $(90 - x)^{\circ}$ .

According to the question:

$(180 - x) + 50 = 3\, (90 - x)$ .

Solve this equation for $x$ :

$x = 20$ .

Thus, this angle would measure should $20^{\circ}$ .

The supplement of this angle would measure $(180 - 20)^{\circ} = 160^{\circ}$ . The complement of this angle would measure $(90 - 20)^{\circ} = 70^{\circ}$ .

Three times the complement of this angle would be $3 \times 70^{\circ} = 210^{\circ}$ , which is indeed $50^{\circ}$ greater than the supplement of this angle.