Answer:
is outside the circle of radius of
centered at
.
Step-by-step explanation:
Let
and
denote the center and the radius of this circle, respectively. Let
be a point in the plane.
Let
denote the Euclidean distance between point
and point
.
In other words, if
is at
while
is at
, then
.
Point
would be inside this circle if
. (In other words, the distance between
and the center of this circle is smaller than the radius of this circle.)
Point
would be on this circle if
. (In other words, the distance between
and the center of this circle is exactly equal to the radius of this circle.)
Point
would be outside this circle if
. (In other words, the distance between
and the center of this circle exceeds the radius of this circle.)
Calculate the actual distance between
and
:
.
On the other hand, notice that the radius of this circle,
, is smaller than
. Therefore, point
would be outside this circle.
Answer:
C
Step-by-step explanation:
The width is 5 yds longer so we can mark out b and d if you multiply 19 and 24 is 456 so you are left with C
Annie is correct, and I’ll tel u why you can make the same triangle but just flip it so it not going the same way see tell me if u got it correct.
The answer is a I'm pretty sure
There is one<span> last step after getting </span>x<span> = </span>3<span>. You must check </span>x<span> = </span>3<span> in the original equation to be sure that </span>x<span> = </span>3<span> does not cause a zero denominator.</span>